使用XPath将XML节点添加到现有的XML [英] Adding XML nodes to an existing XML using XPATH
本文介绍了使用XPath将XML节点添加到现有的XML的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我要求使用XPath将新的XML节点添加到现有的XML。
现有的XML：
<create>
<article>
<identifier>Test</identifier>
</article>
</create>
已使用XSLT(如果从堆栈溢出中的另一个线程获取)：
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:my="my:my">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:variable name="vPop" as="element()*">
<item path="/create/article[1]/id">1</item>
<item path="/create/article[1]/description">bar</item>
<item path="/create/article[1]/name[1]">foo</item>
<item path="/create/article[1]/price[1]/amount">00.00</item>
<item path="/create/article[1]/price[1]/currency">USD</item>
<item path="/create/article[1]/price[2]/amount">11.11</item>
<item path="/create/article[1]/price[2]/currency">AUD</item>
<item path="/create/article[2]/id">2</item>
<item path="/create/article[2]/description">some name</item>
<item path="/create/article[2]/name[1]">some description</item>
<item path="/create/article[2]/price[1]/amount">00.01</item>
<item path="/create/article[2]/price[1]/currency">USD</item>
</xsl:variable>
<xsl:template match="/">
<xsl:sequence select="my:subTree($vPop/@path/concat(.,'/',string(..)))"/>
</xsl:template>
<xsl:function name="my:subTree" as="node()*">
<xsl:param name="pPaths" as="xs:string*"/>
<xsl:for-each-group select="$pPaths"
group-adjacent=
"substring-before(substring-after(concat(., '/'), '/'), '/')">
<xsl:if test="current-grouping-key()">
<xsl:choose>
<xsl:when test=
"substring-after(current-group()[1], current-grouping-key())">
<xsl:element name=
"{substring-before(concat(current-grouping-key(), '['), '[')}">
<xsl:sequence select=
"my:subTree(for $s in current-group()
return
concat('/',substring-after(substring($s, 2),'/'))
)
"/>
</xsl:element>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="current-grouping-key()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:if>
</xsl:for-each-group>
</xsl:function>
</xsl:stylesheet>
<identifier>Test</identifier>)丢失了。请帮助解决此问题。这是一个示例XML，实际的XML包含许多现有的XML节点。
实际结果：
<create>
<article>
<id>1</id>
<description>bar</description>
<name>foo</name>
<price>
<amount>00.00</amount>
<currency>USD</currency>
</price>
<price>
<amount>11.11</amount>
<currency>AUD</currency>
</price>
</article>
<article>
<id>2</id>
<description>some name</description>
<name>some description</name>
<price>
<amount>00.01</amount>
<currency>USD</currency>
</price>
</article>
</create>
预期结果：
<create>
<article>
<identifier>Test</identifier>
<id>1</id>
<description>bar</description>
<name>foo</name>
<price>
<amount>00.00</amount>
<currency>USD</currency>
</price>
<price>
<amount>11.11</amount>
<currency>AUD</currency>
</price>
</article>
<article>
<id>2</id>
<description>some name</description>
<name>some description</name>
<price>
<amount>00.01</amount>
<currency>USD</currency>
</price>
</article>
</create>
推荐答案
这是基于现有函数创建新节点并将其与输入文档方法合并的粗略介绍：
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="3.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
xmlns:my="http://example.com/my-functions"
expand-text="yes">
<xsl:variable name="vPop" as="element()*">
<item path="/create/article[1]/id">1</item>
<item path="/create/article[1]/description">bar</item>
<item path="/create/article[1]/name[1]">foo</item>
<item path="/create/article[1]/price[1]/amount">00.00</item>
<item path="/create/article[1]/price[1]/currency">USD</item>
<item path="/create/article[1]/price[2]/amount">11.11</item>
<item path="/create/article[1]/price[2]/currency">AUD</item>
<item path="/create/article[2]/id">2</item>
<item path="/create/article[2]/description">some name</item>
<item path="/create/article[2]/name[1]">some description</item>
<item path="/create/article[2]/price[1]/amount">00.01</item>
<item path="/create/article[2]/price[1]/currency">USD</item>
</xsl:variable>
<xsl:variable name="new-nodes">
<xsl:sequence select="my:subTree($vPop/@path/concat(.,'/',string(..)))"/>
</xsl:variable>
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/" name="xsl:initial-template">
<xsl:sequence select="my:merge(*, $new-nodes/*)"/>
</xsl:template>
<xsl:function name="my:merge" as="node()*">
<xsl:param name="node1" as="node()*"/>
<xsl:param name="node2" as="node()*"/>
<xsl:for-each-group select="$node1, $node2" group-by="path()">
<xsl:copy>
<xsl:sequence select="my:merge(@*, current-group()[2]/@*)"/>
<xsl:sequence select="my:merge(node(), current-group()[2]/node())"/>
</xsl:copy>
</xsl:for-each-group>
</xsl:function>
<xsl:function name="my:subTree" as="node()*">
<xsl:param name="pPaths" as="xs:string*"/>
<xsl:for-each-group select="$pPaths"
group-adjacent=
"substring-before(substring-after(concat(., '/'), '/'), '/')">
<xsl:if test="current-grouping-key()">
<xsl:choose>
<xsl:when test=
"substring-after(current-group()[1], current-grouping-key())">
<xsl:element name=
"{substring-before(concat(current-grouping-key(), '['), '[')}">
<xsl:sequence select=
"my:subTree(for $s in current-group()
return
concat('/',substring-after(substring($s, 2),'/'))
)
"/>
</xsl:element>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="current-grouping-key()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:if>
</xsl:for-each-group>
</xsl:function>
</xsl:stylesheet>
但大多数合并要求比我在那里展示的简单my:merge复杂得多，因此您需要细化该函数。
这篇关于使用XPath将XML节点添加到现有的XML的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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