从给定变量中提取随机整数 [英] Extracting random integers from a given variable

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本文介绍了从给定变量中提取随机整数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的任务是在时间间隔500时间内随机挑选3年用于模拟目的。

更具体地说,我想从20072016(10年)中选择3随机年份,例如200820122014。因此,这或多或少等同于从变量中提取随机整数。

我的解决方案如下:

* The following (empty) dataset will be used to append the results of the Monte Carlo simulations
use "recession_parms.dta", clear
save "ind_simulations.dta", replace

forvalues i=1(1)500 {

use reg_sample.dta, clear

di "SIMULATION `i'"

scalar define lowest_year=2007
scalar define highest_year=2016

// randomly select "faked" year1: not inclue real treated years
gen year1_random=(lowest_year+int((highest_year-lowest_year+1)*runiform()))  //To generate random integers over [a,b], use a+int((b-a+1)*runiform()) (see STATA help)
gen temp1 = inlist(year1_random,2008,2012,2014)
while temp1==1 {
    replace year1_random =(lowest_year+int((highest_year-lowest_year+1)*runiform()))
    cap drop temp1
    gen temp1 = inlist(year1_random,2008,2012,2014)
}

// randomly select "faked" year2: (1)not inclue real treated years and (2)not equal to year1
gen year2_random=(lowest_year+int((highest_year-lowest_year+1)*runiform())) 
gen temp2 = inlist(year2_random,2008,2012,2014)
while temp2==1|year1_random==year2_random {
    replace year2_random = lowest_year+int((highest_year-lowest_year+1)*runiform()))
    cap drop temp2
    gen temp2 = inlist(year2_random,2008,2012,2014)
}

// randomly select ""faked" year3_random:(1)not inclue real treated years and (2)not equal to year1 or year2
gen year3_random=(lowest_year+int((highest_year-lowest_year+1)*runiform())) 
gen temp3 = inlist(year2_random,2008,2012,2014)
while temp3==1|year1_random==year3_random|year2_random==year3_random {
    replace year3_random =(lowest_year+int((highest_year-lowest_year+1)*runiform()))
    cap drop temp3
    gen temp3 = inlist(year3_random,2008,2012,2014)
}


drop temp*

* Generate the new treated year dummies
gen recession = (year==year1_random|year==year2_random |year==year3_random)



* Regression
di "SIMULATION `i'"
qui  xtreg freq recession $city_control trend trend_sq ,fe cluster(city) 
parmest,format(estimate min95 max95 %8.2f p %8.3f) saving("temp.dta", replace)


* Append the results of the simulation
use "temp.dta", clear
keep if parm=="recession"
append using "ind_simulations.dta"
save "ind_simulations.dta", replace
}
erase "temp.dta"

use "ind_simulations.dta", clear
drop if estimate==.
save "ind_simulations.dta", replace

有没有什么很好的方法来实现我的目标,而不是编写几个while循环?

推荐答案

以下适用于我:

sysuse uslifeexp, clear
set seed 12345

tempname sim
postfile `sim' id year1 year2 year3 using results, replace

forvalues i = 1 / 500 {
    generate random = runiform()
    sort random
    post `sim' (`i') (year[1]) (year[2]) (year[3])
    drop random
}

postclose `sim'

下面您可以看到生成的results数据集中的前十个观察结果:

use results, clear

list in 1/10

     +----------------------------+
     | id   year1   year2   year3 |
     |----------------------------|
  1. |  1    1927    1920    1910 |
  2. |  2    1946    1917    1925 |
  3. |  3    1927    1926    1946 |
  4. |  4    1916    1908    1963 |
  5. |  5    1983    1913    1967 |
     |----------------------------|
  6. |  6    1926    1967    1974 |
  7. |  7    1976    1947    1927 |
  8. |  8    1908    1960    1982 |
  9. |  9    1947    1989    1915 |
 10. | 10    1950    1920    1975 |
     +----------------------------+

这篇关于从给定变量中提取随机整数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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