Html.RenderPartial不产生值 [英] Html.RenderPartial does not produce a value

问题描述

美好的一天，所有的。

Good day, all.

我知道，这是在MVC方面有pretty基本的问题，但我不能为我得到@ Html.RenderPartial的生活没有给我的错误。我使用VB.NET和剃刀。我已经在网上找到的大多数示例都是用C＃，这是不是我很难转换，但这个简单的一个人把我难住了。这是我的索引视图，即正在由_Layout.vbhtml呈现：

I know that this is a pretty basic question in terms of MVC, but I can not for the life of me get @Html.RenderPartial to not give me errors. I am using VB.NET, and Razor. Most examples that I have found online are written in c#, which isn't hard for me to convert, but this simple one has got me stumped. This is in my Index view, that is being rendered by the _Layout.vbhtml:

@Section MixPage
    @Html.RenderPartial("_MixScreen", ViewData.Model)
End Section

上面的前pression不会产生一个值。

The above expression does not produce a value.

我今天早上看了很长一段时间，并且是我采取的例子页面如下：

I have looked for quite a while this morning, and the pages that I am taking examples from are as follows:

<一个href=\"http://geekswithblogs.net/blachniet/archive/2011/08/03/walkthrough-updating-partial-views-with-unobtrusive-ajax-in-mvc-3.aspx\" rel=\"nofollow\">http://geekswithblogs.net/blachniet/archive/2011/08/03/walkthrough-updating-partial-views-with-unobtrusive-ajax-in-mvc-3.aspx

<一个href=\"http://stackoverflow.com/questions/286132/asp-net-mvc-getting-a-partial-views-html-from-inside-of-the-controller\">ASP.net MVC：从控制器内获取局部视图的HTML

ASP.net MVC: Getting a Partial View's HTML from inside of the controller

最后，我所要做的是回归和更新模型从控制器的局部视图：

Ultimately, what I am trying to do is return and updated model to a partial view from the controller:

    Function UpdateFormulation(model As FormulationModel) As ActionResult
        model.GetCalculation()
        Return PartialView("_MixScreen", model)
    End Function

和该控制器正在从在JavaScript中前pression名为：

and that controller is being called from an expression in javascript:

function UpdateResults() {
    jQuery.support.cors = true;
    var theUrl = '/Home/UpdateFormulation/';
    var formulation = getFormulation();
    $.ajax({
        type: "POST",
        url: theUrl,
        contentType: "application/json",
        dataType: "json",
        data: JSON.stringify(formulation),
        success: function (result, textStatus) {
            result = jQuery.parseJSON(result.d);
            if (result.ErrorMessage == null) {
                FillMixScreen(result);
            } else {
                alert(result.ErrorMessage);
            }
        },
        error: function (xhr, result) {
            alert("readyState: " + xhr.readyState + "\nstatus: " + xhr.status);
            alert("responseText: " + xhr.responseText);
        }
    });
}

如果有更好的方法来此更新的模型返回视图，仅更新我所有的耳朵这个局部视图。但这个问题的premise是：为什么不的RenderPartial产生值

If there is a better way to return this updated model to the view and only update this partial view I am all ears. But the premise of this questions is: Why does RenderPartial not produce a value?

推荐答案

好了，客户端的问题，那就是你在期待一个 HTML 不是一个JSON你客户端，记住，返回一个视图，基本上你返回查看编译它是在 HTML 改变预期结果中的数据类型为HTML

Well, the problem from the client it's that you're expecting an html not a Json in your client, remember that that Return a view, basically you're returning the view compile which's the html change the datatype expected in your result to html

$.ajax({
    type: "POST",
    url: theUrl,
    contentType: "application/json",
    dataType: "html",
    data: JSON.stringify(formulation),
    success: function (result, textStatus) {
        result = jQuery.parseJSON(result.d);
        if (result.ErrorMessage == null) {
            FillMixScreen(result);
        } else {
            alert(result.ErrorMessage);
        }
    },
    error: function (xhr, result) {
        alert("readyState: " + xhr.readyState + "\nstatus: " + xhr.status);
        alert("responseText: " + xhr.responseText);
    }
});

此外，我建议你使用的方法负荷，这是阿贾克斯的短版和假定总是期望的结果这是一个html和它; S追加到你需要

Also I recommend you that use the method load, which is a short version of the ajax and assumes always that the expected result it's a html and it;s appended to the body of the element that you need

二。如果要加载的部分从布局做这样

Second. If you want to load the partial From your layout do it like this

 //note's that i'm calling the action no the view
 @Html.Action("UpdateFormulation","yourController", new { model = model}) //<--- this is code in c# don't know how is in vb

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