SWIFT获取WiFi和蜂窝网络中当前设备的IP地址 [英] Swift Get IP address of current device in wifi and cellular

问题描述

   func getIPAddress() -> String {
    var address: String?
    var ifaddr: UnsafeMutablePointer<ifaddrs>? = nil
    if getifaddrs(&ifaddr) == 0 {
        var ptr = ifaddr
        while ptr != nil {
            defer { ptr = ptr?.pointee.ifa_next }

            let interface = ptr?.pointee
            let addrFamily = interface?.ifa_addr.pointee.sa_family
            if addrFamily == UInt8(AF_INET) || addrFamily == UInt8(AF_INET6) {

                // wifi = ["en0"]
                // wired = ["en2", "en3", "en4"]
                // cellular = ["pdp_ip0","pdp_ip1","pdp_ip2","pdp_ip3"]

                let name: String = String(cString: (interface!.ifa_name))
                if  name == "en0" || name == "en2" || name == "en3" || name == "en4" || name == "pdp_ip0" || name == "pdp_ip1" || name == "pdp_ip2" || name == "pdp_ip3" {
                    var hostname = [CChar](repeating: 0, count: Int(NI_MAXHOST))
                    getnameinfo(interface?.ifa_addr, socklen_t((interface?.ifa_addr.pointee.sa_len)!), &hostname, socklen_t(hostname.count), nil, socklen_t(0), NI_NUMERICHOST)
                    address = String(cString: hostname)
                }
            }
        }
        freeifaddrs(ifaddr)
    }
    return address ?? ""
}

我已经使用了这个程序，并在iOS模拟器中运行了程序，它的值为零。我已添加桥接头文件和#Include。

用于检索我已使用的值

let stringIPAddress : String = self.getIPAddress()

我能知道用模拟器可以获取IP地址吗

推荐答案

我一直在使用这个代码，它已经在模拟器和操场上运行：

public class EnumerateNetworkInterfaces {
    public struct NetworkInterfaceInfo {
        let name: String
        let ip: String
        let netmask: String
    }
    public static func enumerate() -> [NetworkInterfaceInfo] {
        var interfaces = [NetworkInterfaceInfo]()

        // Get list of all interfaces on the local machine:
        var ifaddr : UnsafeMutablePointer<ifaddrs>? = nil
        if getifaddrs(&ifaddr) == 0 {

            // For each interface ...
            var ptr = ifaddr
            while( ptr != nil) {

                let flags = Int32(ptr!.pointee.ifa_flags)
                var addr = ptr!.pointee.ifa_addr.pointee

                // Check for running IPv4, IPv6 interfaces. Skip the loopback interface.
                if (flags & (IFF_UP|IFF_RUNNING|IFF_LOOPBACK)) == (IFF_UP|IFF_RUNNING) {
                    if addr.sa_family == UInt8(AF_INET) || addr.sa_family == UInt8(AF_INET6) {

                        var mask = ptr!.pointee.ifa_netmask.pointee

                        // Convert interface address to a human readable string:
                        let zero  = CChar(0)
                        var hostname = [CChar](repeating: zero, count: Int(NI_MAXHOST))
                        var netmask =  [CChar](repeating: zero, count: Int(NI_MAXHOST))
                        if (getnameinfo(&addr, socklen_t(addr.sa_len), &hostname, socklen_t(hostname.count),
                                        nil, socklen_t(0), NI_NUMERICHOST) == 0) {
                            let address = String(cString: hostname)
                            let name = ptr!.pointee.ifa_name!
                            let ifname = String(cString: name)


                            if (getnameinfo(&mask, socklen_t(mask.sa_len), &netmask, socklen_t(netmask.count),
                                            nil, socklen_t(0), NI_NUMERICHOST) == 0) {
                                let netmaskIP = String(cString: netmask)

                                let info = NetworkInterfaceInfo(name: ifname,
                                                                ip: address,
                                                                netmask: netmaskIP)
                                interfaces.append(info)
                            }
                        }
                    }
                }
                ptr = ptr!.pointee.ifa_next
            }
            freeifaddrs(ifaddr)
        }
        return interfaces
    }
}

然后您可以这样做：

for interface in EnumerateNetworkInterfaces.enumerate() {
    print("(interface.name):  (interface.ip)")
}

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