按XPath查找元素。如何拆分XPath中我不想要的元素 [英] Find element by Xpath. How to split the element I don't want inside the Xpath
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问题描述
我尝试使用Selify来创建一个网站。 当我尝试获取硬币名称时,遇到了一个问题。因为‘td’中有2个元素 我怎样才能摆脱另一个我不想要的元素。或者只跟踪它的第一个元素。 (我找到了这个post,但我不确定它是否解决了我的问题)
这是我的全部代码
#driver chrome def
website = 'https://www.bitkub.com/fee/cryptocurrency'
path = r"C:\Users\USER\Downloads\chromedriver.exe"
options = Options()
options.add_argument("start-maximized")
driver = webdriver.Chrome(service=Service(ChromeDriverManager().install()), options=options)
driver.get(website)
#giving variable
coin_name = [my_elem.text for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//tbody//tr//td[2]//span")))]
chain_name = [my_elem.text for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//tbody//tr//td[3]//div")))]
withdrawal_fees = [my_elem.text for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//tbody//tr//td[4]//div")))]
#print(coin_name)
#print(chain_name)
#print(withdrawal_fees)
#for loop make list
for coin, chains, wdf in zip(coin_name, chain_name, withdrawal_fees):
print("Coin name: {} Chain: {} Fee: {}".format(coin, chains, wdf))
Coin_NAME的输入(我提到它有两个元素)
['Civic(CVC)', '(CVC)', 'Bitcoin SV(BSV)', '(BSV)', 'Ethereum(ETH)', '(ETH)', 'Bitkub Coin(KUB)', '(KUB)', 'Compound(COMP)', '(COMP)', 'Curve DAO Token(CRV)', '(CRV)', .... ]
这是网站上的元素的外观
我希望输入是这样的,这样我就可以从中创建数据帧
['Civic(CVC)', 'Bitcoin SV(BSV)', 'Ethereum(ETH)', 'Bitkub Coin(KUB)', 'Compound(COMP)', 'Curve DAO Token(CRV)', .... ]
推荐答案
根据您当前的输出:
['Civic(CVC)', '(CVC)', 'Bitcoin SV(BSV)', '(BSV)', 'Ethereum(ETH)', '(ETH)', 'Bitkub Coin(KUB)', '(KUB)', 'Compound(COMP)', '(COMP)', 'Curve DAO Token(CRV)', '(CRV)', .... ]
您可以跳过每个备选元素,使用list comprehension创建一个新列表,如下所示:
# coin_name = [my_elem.text for my_elem in WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//tbody//tr//td[2]//span")))]
coin_name = ['Civic(CVC)', '(CVC)', 'Bitcoin SV(BSV)', '(BSV)', 'Ethereum(ETH)', '(ETH)', 'Bitkub Coin(KUB)', '(KUB)', 'Compound(COMP)', '(COMP)', 'Curve DAO Token(CRV)', '(CRV)']
res = [coin_name[i] for i in range(len(coin_name)) if i % 2 == 0]
print (res)
控制台输出:
['Civic(CVC)', 'Bitcoin SV(BSV)', 'Ethereum(ETH)', 'Bitkub Coin(KUB)', 'Compound(COMP)', 'Curve DAO Token(CRV)']
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