如何调用$阿贾克斯误差函数用C＃MVC4？ [英] How to call error function in $.ajax with c# MVC4?

问题描述

我在MVC4与C＃项目。在这个项目中，我的控制器中的一个有一个方法由一个Ajax函数被调用：

I have a project in MVC4 with C#. In this project, one of my controllers has a method to be called by an Ajax function:

[HttpPost]
public string EditPackage(int id, string newPkgName)
{
    try{
        //do logic here
        return "OK";
    }catch(Exception exc){
        return "An error occurred, please try later! " + exc.Message;
    }
}

此方法由下列Ajax函数调用，使用jQuery

This method is called by the following Ajax functions, using jQuery:

$.ajax({
    url: $(this).data('url'),
    type: 'POST',
    contentType: 'application/json; charset=utf-8',
    traditional: true,
    data: JSON.stringify({ id: id, newPkgName: newPkgName}),
    success: function () {
        location.reload(true);
        successNotification("Package edited successfuly!");
    },
    error: function (message) {
        errorNotification(message);
    }
});

本code的问题是，即使服务器返回返回时发生错误，请稍后再试！+ exc.Message; 信息在catch，成功的功能总是叫之一。

The problem with this code, is that even if the server returns the return "An error occurred, please try later! " + exc.Message; message in the catch, the success function is the one always called.

为了话，我从来不管我做什么运行错误的功能。

In order words, I never run the error function no matter what I do.

要解决这个问题我查了一下官方文档：

To fix this I checked the official documentation:

• http://api.jquery.com/jQuery.ajax/

• http://api.jquery.com/jQuery.ajax/

不过，由于我failry新来这个我不明白任何参数，也不怎么有效地使用它们。

However, since I am failry new to this I can't understand any of the parameters, nor how to use them effectively.

我怎样才能创造一个良好的错误消息，使用Ajax，jQuery和我的控制器？

How can I create a good error message with all the possible information using Ajax, jQuery and my controller?

推荐答案

的 $。阿贾克斯错误部分>只调用火灾如果返回的状态code是以外的任何其他 200 OK 。在你的情况你是返回一个明文响应，因此这将是 200 。你可以改变这样的这种行为：

The error part of the $.ajax call only fires if the returned status code is anything other than 200 OK. In your case you are returning a plaintext response which will therefore be 200. You can change this behaviour like this:

try {
    // do logic here
    return "OK";
}
catch (Exception exc) {
    return new HttpStatusCodeResult(HttpStatusCode.BadRequest, "Bad Request");
}

error: function (jqXHR, textStatus, errorThrown) {
    errorNotification(textStatus);
}

您可以修改的HTTPStatus code 来任何适合您的需要。

You can change the HttpStatusCode to whatever suits your need.

另外，你可以保持 200 响应，并用标志返回JSON指示请求是否成功：

Alternatively, you can keep the 200 response and return JSON with a flag to indicate whether or not the request was successful:

[HttpPost]
public ActionResult EditPackage(int id, string newPkgName)
{
    try {
        //do logic here
        return Json(new { Success = true, Message = "OK"});
    }
    catch (Exception exc) {
        return Json(new { Success = false, Message = "An error occurred, please try later! " + exc.Message });
    }
}

然后就可以删除错误处理，并检查标志的状态在成功处理程序：

Then you can remove the error handler, and check the state of the flag in your success handler:

success: function(response) {
    if (response.Success) {
        location.reload(true);
        successNotification("Package edited successfuly!");
    }
    else {
        errorNotification(response.Message); 
    }
},

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