的Python：创建对象和属性添加到它 [英] Python: create object and add attributes to it

问题描述

我要在Python中创建一个动态对象（另一个对象中），然后添加属性给它。

I want to create a dynamic object (inside another object) in Python and then add attributes to it.

我试过：

obj = someobject
obj.a = object()
setattr(obj.a, 'somefield', 'somevalue')

但这并没有工作。

but this didn't work.

任何想法？

的编辑：的

我设置从为循环它通过值列表，例如

I am setting the attributes from a for loop which loops through a list of values, e.g.

params = ['attr1', 'attr2', 'attr3']
obj = someobject
obj.a = object()

for p in params:
   obj.a.p # where p comes from for loop variable

在上面的例子中我会得到 obj.a.attr1 ， obj.a.attr2 ， obj.a.attr3 。

In the above example I would get obj.a.attr1, obj.a.attr2, obj.a.attr3.

我用 SETATTR 函数，因为我不知道该怎么办 obj.a.NAME 从为循环。

I used the setattr function because I didn't know how to do obj.a.NAME from a for loop.

如何我设置属性根据 P 在上面的例子中的价值？

How would I set the attribute based on the value of p in the example above?

推荐答案

您可以用我的古代<一个href=\"http://$c$c.activestate.com/recipes/52308-the-simple-but-handy-collector-of-a-bunch-of-named/?in=user-97991\">Bunch食谱，但如果你不想做一个帮班，一个非常简单的已经存在的Python - 所有的功能都可以任意属性（包括lambda函数）。因此，下面的工作：

You could use my ancient Bunch recipe, but if you don't want to make a "bunch class", a very simple one already exists in Python -- all functions can have arbitrary attributes (including lambda functions). So, the following works:

obj = someobject
obj.a = lambda: None
setattr(obj.a, 'somefield', 'somevalue')

无论是相比于古老的束配方清晰度的损失是确定的，是一种风格的决定，当然，我会离开你来决定。

Whether the loss of clarity compared to the venerable Bunch recipe is OK, is a style decision I will of course leave up to you.

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