从标题数据 - *的jQuery? [英] from title to data-* by jQuery?
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问题描述
我有一个div元素
< DIV CLASS =test2的标题=空白处输入=淡入退出=淡出,scaleOut DUR = 1.2> blahblahblah< / DIV>
在魔术jQuery脚本我想,这将是像
< DIV CLASS =test2的数据输入=淡入数据出境=淡出scaleOut数据持续时间=1.2称号=空白处输入=淡入退出=淡出,scaleOut DUR = 1.2>等等等等等等
< / DIV>
所以,我想这个操纵
<脚本>
$(文件)。就绪(函数(){
$([标题* ='空间'])。每个(函数(){
VAR标题= $(本).attr('标题');
变种titleArray = title.split();
$(本).attr(数据输入,titleArray [1]);
$(本).attr(数据出境,titleArray [2]);
$(本).attr(数据持续时间,titleArray [3]);
$(本).removeAttr(标题);
});
});
< / SCRIPT>
不过,这并不正常工作,因为我有数据出口=淡出scaleOut具有两个属性,我的剧本是这样的div
< DIV CLASS =test2的标题=空间淡入淡出1.2> blahblahblah< / DIV>
但我不想要它。
也许你知道在这个例子正确的解决方案。也许有些人觉得还是replaceWith功能将有助于这一点。
谢谢。我希望你明白我的问题。
解决方案
我觉得这是正规的前pressions工作。事情是这样的:
\r
\r\r
\r $([标题* ='空间'])。每个(函数(){\r
\r
VAR标题= this.title,\r
输入= this.title.match(/输入=(*)(\\ S |?$)/)\r
退出= this.title.match(/退出=(*)(\\ S |?$)/)\r
持续时间= this.title.match(?/ DUR =(*)(\\ S | $)/)\r
\r
$(本).attr(数据输入,输入[1]);\r
$(本).attr(数据退出,退出[1] .replace(/,/,''));\r
$(本).attr(数据持续时间,持续时间[1]);\r
$(本).removeAttr(标题);\r
});
\r
&LT;脚本SRC =https://ajax.googleapis.com/ajax /libs/jquery/2.1.1/jquery.min.js\"></script>\r
&LT; DIV CLASS =test2的标题=空白处输入=淡入退出=淡出,scaleOut DUR = 1.2&GT; blahblahblah&LT; / DIV&GT;
\r
I have a div element
<div class="test2" title="space enter=fadeIn exit=fadeout,scaleOut dur=1.2" >blahblahblah</div>
After magic jQuery script I want that it will be like that
<div class="test2" data-enter="fadeIn" data-exit="fadeOut scaleOut" data-duration="1.2" title="space enter=fadeIn exit=fadeout,scaleOut dur=1.2" > blahblahblah
</div>
So I tried to manipulate with this
<script>
$( document ).ready(function() {
$("[title*='space']").each(function() {
var title = $(this).attr('title');
var titleArray = title.split(" ");
$(this).attr("data-enter", titleArray[1]);
$(this).attr("data-exit", titleArray[2]);
$(this).attr("data-duration", titleArray[3]);
$(this).removeAttr('title');
});
});
</script>
But it doesn't work properly, cause I have data-exit="fadeOut scaleOut" with two properties and my script is for div like that
<div class="test2" title="space fadeIn fadeout 1.2" >blahblahblah</div>
But I don't want it. Maybe you know right solution for this example. Maybe some find or replaceWith function will help for this. Thanks. I hope you understood my question.
解决方案
I think this is job for regular expressions. Something like this:
$("[title*='space']").each(function() {
var title = this.title,
enter = this.title.match(/enter=(.*?)(\s|$)/),
exit = this.title.match(/exit=(.*?)(\s|$)/),
duration = this.title.match(/dur=(.*?)(\s|$)/)
$(this).attr("data-enter", enter[1]);
$(this).attr("data-exit", exit[1].replace(/,/, ' '));
$(this).attr("data-duration", duration[1]);
$(this).removeAttr('title');
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="test2" title="space enter=fadeIn exit=fadeout,scaleOut dur=1.2" >blahblahblah</div>
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