如何拼接的音频文件（WAV格式）转换成在python 1秒接头？ [英] How to splice an audio file (wav format) into 1 sec splices in python?

问题描述

我要寻找一个Python函数拼接的音频文件（WAV格式）到1秒的持续时间接头和每一个新的接头（1秒的持续时间）的存储到一个新的.wav文件。

I am looking for a python function to splice an audio file (wav format) into 1 sec duration splices and store each of the new splices (of 1 sec duration ) into a new .wav file.

推荐答案

其真正的简单，使用 pydub 模块的细节容易，其中超过的这里和这里

Its real simple and easy using pydub module, details of which are over here and here

pydub 有一个名为方法 make_chunks 来，你可以指定块长度在毫秒。

pydub has a method called make_chunks to which you can specify chunk length in milliseconds.

make_chunks（your_audio_file_object，chunk_length_ms）

下面是一个工作code，它分割WAV文件在1秒块。我有一个8.5秒文件，所以程序创建91秒块是可玩。最后一个块将根据音频的持续时间比较小。

Here is a working code that splits wav file in one sec chunks. I had a 8.5 seconds file, so the program created 9 one seconds chunks that are playable. Last chunk will be smaller depending on audio duration.

from pydub import AudioSegment
from pydub.utils import make_chunks

myaudio = AudioSegment.from_file("myAudio.wav" , "wav") 
chunk_length_ms = 1000 # pydub calculates in millisec
chunks = make_chunks(myaudio, chunk_length_ms) #Make chunks of one sec

#Export all of the individual chunks as wav files

for i, chunk in enumerate(chunks):
    chunk_name = "chunk{0}.wav".format(i)
    print "exporting", chunk_name
    chunk.export(chunk_name, format="wav")

输出

Python 2.7.9 (default, Dec 10 2014, 12:24:55) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> ================================ RESTART ================================
>>> 
exporting chunk0.wav
exporting chunk1.wav
exporting chunk2.wav
exporting chunk3.wav
exporting chunk4.wav
exporting chunk5.wav
exporting chunk6.wav
exporting chunk7.wav
exporting chunk8.wav
>>> 

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