等到另一种声音是打新的前完成 [英] Waiting until another sound is finished before playing a new one

问题描述

我开发一个播放声音的iPhone应用程序。我不想打断或播放另一种声音，如果声音已在播放，不管它是催生从哪里玩。我的code是如下：

I am developing an iPhone application that plays sounds. I do not want interrupt or play another sound, if a sound is already playing, regardless of where it was "spawned" from to play. My code is as follows:

if(distance <= 10)
{
   NSString *soundPath = [[NSBundle mainBundle] pathForResource:@"sound" ofType:@"wav"];
   SystemSoundID soundID;
   AudioServicesCreateSystemSoundID((CFURLRef)[NSURL fileURLWithPath: soundPath], &soundID);
   AudioServicesPlaySystemSound(soundID); 
}

简单地说，我并不想打一个新的声音如果正在播放。

Simply, I do not want to play a new sound if one is already playing.

我不想排队另一个声音播放如果正在播放。

I do not want to queue another sound to play if one is already playing.

这可能吗？

推荐答案

我建议你使用AVAudioPlayer API，而不是AudioServicesPlaySystemSound。它有一个委托，您可以使用，它定义了一个方法-audioPlayerDidFinishPlaying：成功：它会告诉你，当你的声音播放完毕。该AVPlayer类还有一个方法-playing，你可以检查，看是否有声音正在播放。

I suggest you use the AVAudioPlayer API rather than AudioServicesPlaySystemSound. It has a delegate which you can use, which defines a method -audioPlayerDidFinishPlaying:successfully: which will tell you when your sound finishes playing. The AVPlayer class also has a -playing method which you can check to see if a sound is currently playing.

所以，换句话说，这样做，而不是：

So, in other words, do this instead:

NSError *error;
AVAudioPlayer *player = [[AVAudioPlayer alloc] initWithContentsOfURL:soundPath error:&error];
if(!player)
   [self doSomethingWithError:error];
[player setDelegate:self];
[player play];

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