玩其他的在Java中后，WAV文件中的一个 [英] Play WAV files one after the other in Java

问题描述

我想href=\"http://en.wikipedia.org/wiki/WAV\" rel=\"nofollow\"> WAV文件后，对方打了几个

 为（字符串的文件：语音文件）{
    新AePlayWave（文件）。开始（）;
}
 

但是，播放它们都在同一时间。所以，我需要看起来像这样一个功能：

 公共无效播放（矢量＆lt;串GT;语音文件）;
 

该矢量包含文件，例如：test1.wav，test2.wav

我一直在寻找的四个多小时，但我似乎无法找到一个有效的解决方案：（

我也试过WAV文件串联一个的AudioInputStream。它不给任何编译器错误，但声音完全搞砸了。 code：

 公共静态的AudioInputStream CONCAT（矢量＆lt;串GT;文件）抛出UnsupportedAudioFileException，IOException异常{
    总的AudioInputStream = AudioSystem.getAudioInputStream（新文件（files.get（0）））;    的for（int i = 1; I＆LT; files.size（）;我++）{
        的AudioInputStream夹= AudioSystem.getAudioInputStream（新文件（files.get（I）））;
        总=新的AudioInputStream（新的SequenceInputStream（总，夹子），
                                     total.getFormat（），
                                     total.getFrameLength（）+ clip.getFrameLength（））;
    }
    总回报;
}
 

修改

即使我尝试把前两个文件放在一起，它失败：

 公共静态的AudioInputStream CONCAT（矢量＆lt;串GT;文件）抛出UnsupportedAudioFileException，IOException异常{
    的AudioInputStream clip1 = AudioSystem.getAudioInputStream（新文件（files.get（0）））;
    的AudioInputStream CLIP2 = AudioSystem.getAudioInputStream（新文件（files.get（1）））;    总的AudioInputStream =新的AudioInputStream（
        新的SequenceInputStream（clip1，CLIP2）
        clip1.getFormat（），
        clip1.getFrameLength（）+ clip2.getFrameLength（））;    总回报;
}
 

解决方案

这code是有点低的水平，但它的作品：

 字节[]缓冲区=新的字节[4096];
    对于（文件文件：文件）{
        尝试{
            的AudioInputStream是= AudioSystem.getAudioInputStream（文件）;
            AudioFormat的格式= is.​​getFormat（）;
            SourceDataLine的行= AudioSystem.getSourceDataLine（格式）;
            line.open（格式）;
            line.start（）;
            而（is.available（）大于0）{
                INT LEN = is.​​read（缓冲）;
                line.write（缓冲液，0，LEN）;
            }
            line.drain（）; // ** [DEIT] **等待缓冲关闭前行空
            line.close（）;
        }赶上（例外五）{
            e.printStackTrace（）;
        }
    }
 

基本上，你打开的AudioInputStream，读取数据并将数据写入的SourceDataLine。 写办法阻止，因此会因此播放文件。

您可以尝试使用剪辑为同一目的。

I'm trying to play a few WAV files after each other. I tried this method:

for (String file : audioFiles) {
    new AePlayWave(file).start();
}

But that plays them all at the same time. So I need a function that looks like this:

public void play(Vector<String> audioFiles);

The vector contains the files, for example: "test1.wav","test2.wav"

I have been looking for over four hours, but I can't seem to find a working solution :(

I also tried concatenating the WAV files to one AudioInputStream. It doesn't give any compiler errors, but the sound is totally messed up. Code:

public static AudioInputStream concat(Vector<String> files) throws UnsupportedAudioFileException, IOException {
    AudioInputStream total = AudioSystem.getAudioInputStream(new File(files.get(0)));

    for (int i = 1; i < files.size(); i++) {
        AudioInputStream clip = AudioSystem.getAudioInputStream(new File(files.get(i)));
        total = new AudioInputStream(new SequenceInputStream(total, clip),
                                     total.getFormat(),
                                     total.getFrameLength() + clip.getFrameLength());
    }
    return total;
}

Edit

Even if I try to put the two first files together, it fails:

public static AudioInputStream concat(Vector<String> files) throws UnsupportedAudioFileException, IOException {
    AudioInputStream clip1 = AudioSystem.getAudioInputStream(new File(files.get(0)));
    AudioInputStream clip2 = AudioSystem.getAudioInputStream(new File(files.get(1)));

    AudioInputStream total = new AudioInputStream(
        new SequenceInputStream(clip1, clip2),
        clip1.getFormat(),
        clip1.getFrameLength() + clip2.getFrameLength());

    return total;
}

解决方案

This code is a bit low-level, but it works:

    byte[] buffer = new byte[4096];
    for (File file : files) {
        try {
            AudioInputStream is = AudioSystem.getAudioInputStream(file);
            AudioFormat format = is.getFormat();
            SourceDataLine line = AudioSystem.getSourceDataLine(format);
            line.open(format);
            line.start();
            while (is.available() > 0) {
                int len = is.read(buffer);
                line.write(buffer, 0, len);
            }
            line.drain(); //**[DEIT]** wait for the buffer to empty before closing the line
            line.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

Basically you open an AudioInputStream, read data and write it to a SourceDataLine. write method is blocking, so it will play files consequently.

You can try to use Clip for the same purpose.

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