Java的采样率转换 [英] Java Sampling Rate Conversion

问题描述

在我的Java code，我想44100赫兹的WAV文件转换为8000 Hz的WAV文件。我知道，我必须低通滤波器，然后抽取（+插值）（DSP的理论），但我不想从头开始实现它。

In my Java code, I would like to convert a WAV file of 44100 Hz to a WAV file of 8000 Hz. I know that I have to low-pass filter and then decimate (+interpolate) (the DSP theory) but I do not want to implement it from scratch.

我要寻找一个库，可以有效地做到这一点。你知道有什么？

I am looking for a library that can efficiently do it. Do you know any?

我能够从缓冲区中读取wav文件到一个缓冲区，也写入wav文件到文件，如果它会更容易。

I am able to read wav files into a buffer and also write wav files from buffer to file if it will make it easier.

推荐答案

您应该看看 FMJ 。它提供了ffmpeg的一个包装，可以处理各种转换工作（包括音频重采样）非常有效。

You should look at FMJ. It provides a wrapper for ffmpeg which can handle all sorts of conversion work (including audio resampling) very efficiently.

这篇关于Java的采样率转换的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！