找回用户名，密码通过参数传递卷曲 [英] Retrieve username, password parameters passed through curl

问题描述

我试图发送用户名和密码参数，使用curl一个网址，我想找回它们。我的参数发送到一个页面，如下所示：

I am trying to send username and password parameters to a url using curl, and I want to retrieve them. I send the parameters to a page, like the following:

<?php

$curl = curl_init('http://localhost/sample.php');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);                         
curl_setopt($curl, CURLOPT_USERPWD, 'key:123456');
curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_ANY);                    
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);                          
curl_setopt($curl, CURLOPT_FOLLOWLOCATION, true);                           
curl_setopt($curl, CURLOPT_USERAGENT, 'Sample Code');

$response = curl_exec($curl);                                          
$resultStatus = curl_getinfo($curl);                                   

if($resultStatus['http_code'] == 200) {
    echo $response;
} else {
    echo 'Call Failed '.print_r($resultStatus);                         
}
?>

现在在sample.php页面，我怎么能找回那些参数？
（在这里，用户名是关键，密码为123456）。

Now in the sample.php page, how can I retrieve those parameters? (here, username is key, password is 123456).

我想他们一定是$ _ SERVER数组中可用，但他们是不可用的。

I suppose they must be available in the $_SERVER array, but they are not available.

推荐答案

默认情况下，袅袅发出HTTP GET请求。在这种情况下，你必须参数追加到您所呼叫的网址：

By default, cURL issues an HTTP GET request. In this case, you'd have to append the parameters to the URL you're calling:

$curl = curl_init('http://localhost/sample.php?foo=bar&baz=zoid');

在 sample.php ， $ _ GET ['酒吧'] 和 $ _ GET ['巴兹'] 将分别提供。如果它是一个POST请求，你要发行，则需要通过设置参数 curl_setopt ：

In sample.php, $_GET['bar'] and $_GET['baz'] would be available respectively. If it's a POST request, you want to issue, you'll need to set the parameters via curl_setopt:

$curl = curl_init('http://localhost/sample.php');
curl_setopt($curl, CURLOPT_POSTFIELDS, 'foo=bar&baz=zoid');

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