Java的：与HTTPBasic认证获取网址 [英] Java: fetch URL with HTTPBasic Authentication

问题描述

我在做一些简单的HTTP认证和我得到一个

  java.lang.IllegalArgumentException：如果邮件标头值非法字符（S）：基本OGU0ZTc5ODBk（...从76个字符修剪...）
（...更多密码数据......）
 

我想这是因为我有一个很长的用户名和密码，连接codeR用其包装\\ n 76个字符。有没有什么办法可以解决这个问题？该URL只支持HTTP基本认证。

下面是我的code：

 私有类UserPassAuthenticator扩展验证器{
    字符串的用户;
    字符串传递;
    公共UserPassAuthenticator（用户字符串，字符串通）{
        this.user =用户;
        this.pass =传递;
    }    //此方法时，密码保护的URL访问称为
    受保护的PasswordAut​​hentication的getPasswordAut​​hentication（）{
        返回新的PasswordAut​​hentication（用户，pass.toCharArray（））;
    }
}私人字符串取（StoreAccount帐户，字符串路径）抛出IOException
    Authenticator.setDefault（新UserPassAuthenticator（account.getCredentials（）getLogin（），account.getCredentials（）getPassword来（））。）;    网址URL =新的URL（https开头，account.getStoreUrl（）取代（的http：//，），路径）;
    的System.out.println（URL）;    URLConnection的urlConn = url.openConnection（）;
    对象o = urlConn.getContent（）;
    如果（！（邻的instanceof字符串））
        扔（关于错误的Content-Type+ url.toString（））的新IOException异常;    //删除认证回默认
    Authenticator.setDefault（NULL）;
    返回（字符串）O;
}
 

解决方案

这似乎是在错误Java的的。

您是否尝试过使用替代HTTP客户端，如Apache的图书馆吗？

或代替使用验证器，手动设置标题？

 网​​址URL =新的URL（http://www.example.com/）;
HttpURLConnection的连接=（HttpURLConnection类）url.openConnection（）;
connection.setRequestProperty（授权，基本OGU0ZTc5ODBkABcde ......）;
 

令牌值为en codeBase64（用户名：密码）。

I'm doing some simple HTTP authentication and am getting a

java.lang.IllegalArgumentException: Illegal character(s) in message header value: Basic OGU0ZTc5ODBk(...trimmed from 76 chars...)
(...more password data...)

which I think is due to me having a really long username and password and the encoder wraps it with a \n at 76 chars. Is there any way I can get around this? The URL only supports HTTP Basic Auth.

Here is my code:

private class UserPassAuthenticator extends Authenticator {
    String user;
    String pass;
    public UserPassAuthenticator(String user, String pass) {
        this.user = user;
        this.pass = pass;
    }

    // This method is called when a password-protected URL is accessed
    protected PasswordAuthentication getPasswordAuthentication() {
        return new PasswordAuthentication(user, pass.toCharArray());
    }
}

private String fetch(StoreAccount account, String path) throws IOException {
    Authenticator.setDefault(new UserPassAuthenticator(account.getCredentials().getLogin(), account.getCredentials().getPassword()));

    URL url = new URL("https", account.getStoreUrl().replace("http://", ""), path);
    System.out.println(url);

    URLConnection urlConn = url.openConnection();
    Object o = urlConn.getContent();
    if (!(o instanceof String)) 
        throw new IOException("Wrong Content-Type on " + url.toString());

    // Remove the authenticator back to the default
    Authenticator.setDefault(null);
    return (String) o;
}

解决方案

That seems to be a bug in Java.

Have you tried using alternative HTTP clients, such as the library from Apache?

Or instead of using the Authenticator, manually setting the header?

URL url = new URL("http://www.example.com/");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestProperty("Authorization", "Basic OGU0ZTc5ODBkABcde....");

The token value is encodeBase64("username:password").

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