与API密钥认证的urllib2 [英] Urllib2 authentication with API key

问题描述

我试图连接到 Radian6的API ，这就需要auth_appkey，AUTH_USER和作为AUTH_PASS MD5加密。

I am trying to connect to radian6 api, which requires the auth_appkey, auth_user and auth_pass as md5 encryption.

当我尝试使用telnet连接我可以成功地得到响应XML

When I am trying to connect using telnet I can get the response xml successfully

telnet sandboxapi.radian6.com 80
Trying 142.166.170.31...
Connected to sandboxapi.radian6.com.
Escape character is '^]'.
GET /socialcloud/v1/auth/authenticate HTTP/1.1
host: sandboxapi.radian6.com
auth_appkey: 123456789
auth_user: [e-mail]
auth_pass: 'md5encryptedpassword'

HTTP/1.1 200 OK
Server: Apache-Coyote/1.1
Date: Thu, 26 Aug 2010 14:17:52 GMT
Content-Type: application/xml
Content-Length: 471

但是，当我试图同在Python具有以下code，

But when I am trying the same in python with the following code,

import urllib
import urllib2

user = '[e-mail]'
password = 'md5encryptedpasswrod'
base_url = 'http://sandboxapi.radian6.com/'
api_key = '123456789'

pwman = urllib2.HTTPPasswordMgrWithDefaultRealm()
pwman.add_password(None, base_url, user, password)
auth_handler = urllib2.HTTPBasicAuthHandler(pwman)
opener = urllib2.build_opener(auth_handler)
urllib2.install_opener(opener)

req = urllib2.Request('http://sandboxapi.radian6.com/socialcloud/v1/auth/authenticate')
req.add_header('auth_appkey', api_key)
xml = urllib2.urlopen(req).read()

它抛出下面的错误跟踪，

it is throwing the following error trace,

Traceback (most recent call last):
File "connectapi.py", line 17, in <module>
xml = urllib2.urlopen(req).read()
 File"/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 397, in open
response = meth(req, response)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 510, in http_response
'http', request, response, code, msg, hdrs)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 435, in error
return self._call_chain(*args)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 369, in _call_chain
result = func(*args)
File "/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/urllib2.py", line 518, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 401: Unauthorized

我不知道我错过了什么。难道是API密钥或MD5加密的密码，这就是为什么我被未经授权的？结果
你的智慧会pciated救我一天多少AP $ P $。

I don't know what I am missing. Is it the API key or md5 encrypted password that is why I am being unauthorized?
Your wisdom will be much appreciated to save my day.

推荐答案

在你的远程登录会话，你不设置授权方式：头，但是这就是 HTTPBasicAuthHandler 使用。 （你可以在听这个使用 Wireshark的或相似的。）presumably API不使用HTTP基本身份验证，但其家庭酿造变种。你可能想删除该行并手动设置HTTP标头。

In your telnet session, you're not setting the Authorization: header, but that's what HTTPBasicAuthHandler uses. (You could listen in on this using wireshark or similar.) Presumably the API doesn't use HTTP Basic Authentication but its home-brew variant. You probably want to drop that line and set the HTTP headers manually.

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