如何以编程方式检查Windows机器上打开的浏览器实例？ [英] How do I programmatically check for open browser instances on a Windows machine?

问题描述

我写了Python中的GUI自动化脚本，打开一个网页浏览器，做了一些测试，在浏览器中，然后关闭浏览器。它这样做是在一个循环，通过数十万迭代往上走。

我碰到的问题，该程序会挂起，我会得到任何浏览器实例中打开或有时多达20个实例打开。
我想创建一个错误检查，以确保没有在同一时间只有一个浏览器实例打开（彻底杀灭浏览器，如果有很多实例中打开重启迭代和/或确保浏览器的实例是开放前通过去循环迭代）。

的PID浏览器通过循环的每一次迭代变化明显而据我所知，是没有办法来分配的PID。
我还以为是使系统调用到终端并以某种方式利用任务列表，并使用taskkill命令，但另一种解决方案仍然没有想出一个办法做我想做的。

任何建议将是极大的AP preciated！

更新：

我明白，我可以按名称搜索窗口过程，但我会如何将其写入一个布尔值前pression像

 如果任务列表中包含firefox.exe
    TASKKILL f​​irefox.exe
其他
    打开Firefox
 

第二次更新：

我有我能够在Ruby中code其中工程如下：

 如果系统（任务列表|查找firefox.exe'）==真
        a = 1时
    ELSIF系统（任务列表|查找firefox.exe'）==假
        a = 0时
    结束
 

我怎么会在Python做到这一点？

答案我一直在寻找：

  B =（STR（使用os.system（'任务列表|查找firefox.exe'）））
若B =='1'：
    B =假
ELIF b ==0：
    B =真
印片b
 

解决方案

我一直都在做类似的事情。

我觉得你可能要pywinauto

 从pywinauto.findwindows进口find_windowsfind_windows（best_match ='YOURWINDOWNAMEHERE'）
 

这将引发异常，如果YOURWINDOWNAMEHERE没有打开

编辑：其实对于Firefox或Chrome，它只能当YOURWINDOWNAMEHERE就是不管你是在页面比如这个页面是蟒蛇 - 如何编程......

如果它发现它，它会返回一个int，据我知道这INT应该是能够引用到窗口。

例如：

 ＆GT;＆GT;＆GT; find_windows（best_match =计算器）＃此得到一个异常＃::现在我手动打开计算器::＆GT;＆GT;＆GT; find_windows（best_match =计算器）[12345] #orwhatever进程号它会
 

I wrote a GUI automation script in python that opens a web browser, does some tests in the browser and then closes the browser. It does so in a loop going up through hundreds of thousands of iterations.

I've run into problems where the program would hang and I would get no browser instances open or sometimes up to 20 instances open. I would like to create an error check to make sure there is only one browser instance open at a time (kill the browser completely and restart the iteration if there are many instances open and/or make sure a browser instance is open before going through an iteration of the loop).

The PID for the browser obviously changes through every iteration of the loop and as far as I know, there is no way to assign PIDs. Another solution I thought of is making a system call to the terminal and somehow utilizing the tasklist and taskkill commands but have still not figured out a way to do what I want.

Any suggestions would be greatly appreciated!

Update:

I understand I can search windows processes by name but how would I put that into a boolean expression like

if tasklist contains firefox.exe
    taskkill firefox.exe
else
    open firefox

Second Update:

I have the following that I was able to code in Ruby which works:

    if system('tasklist | find "firefox.exe"') == true
        a = 1
    elsif system('tasklist | find "firefox.exe"') == false
        a = 0
    end

How would I accomplish this in Python?

Answer I was looking for:

b = (str(os.system('tasklist | find "firefox.exe"')))
if b == '1':
    b = 'false'
elif b == '0':
    b = 'true'
print b

解决方案

Ive been doing similar things

i think you may want pywinauto

from pywinauto.findwindows import find_windows

find_windows(best_match='YOURWINDOWNAMEHERE')

this will raise an exception if YOURWINDOWNAMEHERE is not open

edit: actually for firefox or chrome, it only works if "YOURWINDOWNAMEHERE" is whatever the page you are on is for example this page is "python - How do i programmatically ..."

if it finds it, it will return an int, as far as i know this int is supposed to be able to reference to the window.

example:.

>>>find_windows(best_match="calculator")    #this gets an exception

# ::I manually open Calculator now ::

>>>find_windows(best_match="calculator")

[12345] #orwhatever process number it gets

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