如何把序列号只在重复的行结束 [英] How to put sequential numbers only at end of the repeated lines

问题描述

我有一些重复行的文件。我想提出的序列号只在这些重复的结束

I have a file with some repeated lines. I want to put a sequential number only at the end of these repetitions.

例。

输入：

Jose da Silva
Jose da Silva
Fulano de Tal
Jose da Silva
Sicrano Pereira
Ze Ruela
Sicrano Pereira
Jose da Silva

输出：

Jose da Silva #1
Jose da Silva #2
Fulano de Tal
Jose da Silva #3
Sicrano Pereira #1
Ze Ruela
Sicrano Pereira #2
Jose da Silva #4

我不能将这些行进行排序。他们必须出现在同一个数量级。

I cannot sort these lines. They have to appear on the same order.

推荐答案

循环两次：

awk 'FNR==NR {count[$0]++; next} 
     count[$0]>1 {$0=$0 FS "#"++times[$0]}
     1' file file

这就是：第一次，计数每行出现的次数。第二次，保持一个附加递增的数字以那些出现不止一次。

That is: the first time, count how many times each line occurs. The second time, keep appending an incrementing number to those that appear more than once.

$ awk 'FNR==NR {count[$0]++; next} count[$0]>1 {$0=$0 FS "#"++times[$0]}1' file file
Jose da Silva #1
Jose da Silva #2
Fulano de Tal
Jose da Silva #3
Sicrano Pereira #1
Ze Ruela
Sicrano Pereira #2
Jose da Silva #4

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