拆分使用字符串作为分隔符awk的字符串 [英] Split a string using a string as delimiter in awk

问题描述

系统：的Solaris
我试图用分隔符为另一个字符串分割字符串

例如：

---

主字符串： /为/ asdasd / asdasd /根/ asdqwe / ASD / asssdd /

我想从根的子字符串分割成两部分这使得

$ 1 = /为/ asdasd / asdasd /

和

$ 2 = asdqwe / ASD / asssdd /

这是我使用FS实现了code，但它不工作：

 回音/为/ asdasd / asdasd /根/ asdqwe / ASD / asssdd / | AWK
BEGIN {FS =根} {打印$ 2}'
 

解决方案

据在这里工作，除了额外的 / 上你不处理的前面。也许你想根/为您的分隔符？它也可能有必要使用一个新的 AWK ;的Solaris仍然船舶古V7 Unix的 AWK 为的/ usr / bin中/ AWK ，POSIX兼容的 AWK 是的/ usr / bin中/ NAWK 。

System : Solaris I am trying to split a string using the delimiter as another string

For example:

---

The main string is : /as/asdasd/asdasd/root/asdqwe/asd/asssdd/

I wanna split this into two part from the "root" substring such that

$1 = /as/asdasd/asdasd/

and

$2 = asdqwe/asd/asssdd/

This is the code I implemented using FS, but it doesn't work:

echo /as/asdasd/asdasd/root/asdqwe/asd/asssdd/ | awk '
BEGIN { FS = "root" } { print $2 }'

解决方案

It works here, aside from the extra / on the front which you don't handle. Maybe you want "root/" as your delimiter? It may also be necessary to use a newer awk; Solaris still ships the ancient V7 Unix awk as /usr/bin/awk, POSIX-compliant awk is /usr/bin/nawk.

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