如何与服用其他文件的帐户显示文件内容？ [英] How to display content of a file with taking account of other file?

问题描述

我在文件1 ，内容如下

{"name":"clio5", "value":"13"}
{"name":"citroen_c4", "value":"23"}
{"name":"citroen_c3", "value":"12"}
{"name":"golf4", "value":"16"}
{"name":"golf3", "value":"8"}

和我在文件2 ，内容如下

{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"golf4", "value":"18"}

我想，以显示在文件1 的内容执行shell命令，并在文件2 。如果名称中都存在的文件1 和文件2 所以我想只显示在的相关行文件2

I want to execute a shell command in order to display the content of the file1 and the file2. if a name exist in both file1 and file2 so I want to display only the related line of the file2.

所以输出应该是这样的：

So the output should look like this:

$command taking account file1 file2
{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"citroen_c3", "value":"12"}
{"name":"golf4", "value":"18"}
{"name":"golf3", "value":"8"}

该命令不应该修改的文件1 既不文件2

修改

在文件1 和文件2 有exactelly相同的内容格式为：

The file1 and file2 have exactelly the same content format:

{"name":"any", "value":"xx"}

该命令应尽可能简单

The command should be as simple as possible

该命令可以包含的grep ， SED ， AWK

推荐答案

下面是一个办法 AWK ：

awk -F"[:,]" '
NR==FNR { name[$2]=$0;next }
($2 in name) { delete name[$2]; print $0 }
END { for (left in name) print name[left] }' file1 file2

测试：

$ head file*
==> file1 <==
{"name":"clio5", "value":"13"}
{"name":"citroen_c4", "value":"23"}
{"name":"citroen_c3", "value":"12"}
{"name":"golf4", "value":"16"}
{"name":"golf3", "value":"8"}

==> file2 <==
{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"golf4", "value":"18"}

$ awk -F"[:,]" '
NR==FNR { name[$2]=$0;next }
($2 in name) { delete name[$2]; print $0 }
END { for (left in name) print name[left] }' file1 file2
{"name":"clio5", "value":"14"}
{"name":"citroen_c4", "value":"25"}
{"name":"golf4", "value":"18"}
{"name":"golf3", "value":"8"}
{"name":"citroen_c3", "value":"12"}

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