要使用条件列求和 [英] To sum column with condition

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本文介绍了要使用条件列求和的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在文本文件的数据。例。

  A B C D E F
10 0 0.9775 39.3304 60.5601 0.9311
10 1 0.9802 32.3287 0.9433 56.1201
10 2 0.9816 39.9759 0.9446 54.0428
10 3 0.9737 37.8779 0.9419 56.3865
10 4 0.9798 34.9152 0.905 69.0879
10 5 0.9803 50.057 0.9201 64.6289
10 6 0.9805 39.1062 0.9093 68.4061
10 7 0.9781 33.8874 0.9327 60.7631
10 8 0.9802 32.5734 0.9376 60.9165
109 0.9798 32.3466 0.94 54.7645
11 0 0.9749 40.2712 0.9042 71.2873
11 1 0.9755 35.6546 0.9195 63.7436
11 2 0.9766 36.753 0.9507 51.7864
11月3日0.9779 35.6485 0.9371 59.2483
11 4 0.9803 35.2712 0.8833 79.0257
11月5 0.981 46.5462 0.9156 66.6951
11月6日0.9809 41.8181 0.8642 83.7533
11月7日0.9749 36.7484 0.9259 62.36
11月8日0.9736 36.8859 0.9395 58.1538
11月9日0.98 32.4069 0.9255 61.202
12 0 0.9812 37.2547 0.9121 68.1347
12 1 0.9808 31.4568 0.9372 55.9992
12 2 0.9813 36.5316 0.9497 53.1687
12月3日0.9803 33.1063 0.9051 69.8894
12 4 0.9786 35.0318 0.8968 72.9963
12 5 0.9756 63.441 0.9091 69.9482
12月6日0.9804 39.1602 0.9156 65.2399
12月7日0.976 35.5875 0.9248 62.6284
12月8日0.9779 33.7774 0.9416 56.3755
12月9日0.9804 32.0849 0.9401 55.2871

欲列C的随着条件的总和。 A列的值是否是唯一的(10行)。请告诉我。


解决方案

 开放('data.txt中')为f:
    下一个(F)
    D =快译通()
    对于F中的X:
        如果x.split()[0]没有在d:
            D [x.split()[0]] =浮子(x.split()[2])
        其他:
            D [x.split()[0] + =浮子(x.split()[2])

输出:

  {'11':9.7756,'10':9.791699999999999,'12':9.7925}

I have data in textfile. example.

A B C D E F
10 0 0.9775 39.3304 0.9311 60.5601
10 1 0.9802 32.3287 0.9433 56.1201
10 2 0.9816 39.9759 0.9446 54.0428
10 3 0.9737 37.8779 0.9419 56.3865
10 4 0.9798 34.9152 0.905 69.0879
10 5 0.9803 50.057 0.9201 64.6289
10 6 0.9805 39.1062 0.9093 68.4061
10 7 0.9781 33.8874 0.9327 60.7631
10 8 0.9802 32.5734 0.9376 60.9165
10 9 0.9798 32.3466 0.94 54.7645
11 0 0.9749 40.2712 0.9042 71.2873
11 1 0.9755 35.6546 0.9195 63.7436
11 2 0.9766 36.753 0.9507 51.7864
11 3 0.9779 35.6485 0.9371 59.2483
11 4 0.9803 35.2712 0.8833 79.0257
11 5 0.981 46.5462 0.9156 66.6951
11 6 0.9809 41.8181 0.8642 83.7533
11 7 0.9749 36.7484 0.9259 62.36
11 8 0.9736 36.8859 0.9395 58.1538
11 9 0.98 32.4069 0.9255 61.202
12 0 0.9812 37.2547 0.9121 68.1347
12 1 0.9808 31.4568 0.9372 55.9992
12 2 0.9813 36.5316 0.9497 53.1687
12 3 0.9803 33.1063 0.9051 69.8894
12 4 0.9786 35.0318 0.8968 72.9963
12 5 0.9756 63.441 0.9091 69.9482
12 6 0.9804 39.1602 0.9156 65.2399
12 7 0.976 35.5875 0.9248 62.6284
12 8 0.9779 33.7774 0.9416 56.3755
12 9 0.9804 32.0849 0.9401 55.2871

I want the sum of column C. With the condition that. Column A has a value that is unique (10 lines). Please advise me.

解决方案

with open('data.txt') as f:
    next(f)
    d=dict()
    for x in f:
        if x.split()[0] not in d:
            d[x.split()[0]]=float(x.split()[2])
        else:
            d[x.split()[0]]+=float(x.split()[2])

output:

{'11': 9.7756, '10': 9.791699999999999, '12': 9.7925}

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