摧毁骨干集合每个型号干净的方式？ [英] Cleanest way to destroy every Model in a Collection in Backbone?

问题描述

在我写的第一次尝试

this.collection.each(function(element){
    element.destroy();
});

这是不行的，因为它是在Java中，每一个其他元素被删除类似于 ConcurrentModificationException的。

This does not work, because it's similar to ConcurrentModificationException in Java where every other elements are removed.

我想结合的模式删除事件，以毁灭自己的建议<一href=\"http://stackoverflow.com/questions/6280553/destroying-a-backbone-model-in-a-collection-in-one-step\">Destroying在集合的骨干示范一步到位？，但这将火2的删除请求，如果我呼吁摧毁属于集合的典范。

I tried binding "remove" event at the model to destroy itself as suggested Destroying a Backbone Model in a Collection in one step?, but this will fire 2 delete requests if I call destroy on a model that belongs to a collection.

我看着下划线doc和不能看到循环倒退每（）的变体，这将解决取出的每一个元素的问题。

I looked at underscore doc and can't see a each() variant that loops backwards, which would solve the removing every element problem.

您有什么建议，以破坏模型的集合，最彻底的方法？

What would you suggest as the cleanest way to destroy a collection of models?

感谢

推荐答案

您也可以使用一个良好的，ol'派弹出破坏就地：

You could also use a good, ol'-fashioned pop destroy-in-place:

var model;

while (model = this.collection.first()) {
  model.destroy();
}

这篇关于摧毁骨干集合每个型号干净的方式？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！