启动一个程序没有控制台窗口（背景） [英] start a program without a console window (in background)

问题描述

我要开始一个简单的程序，当Windows启动，但我不希望显示与该计划相关的控制台输出窗口。只是为了测试，程序可以是简单的：

I want to start a simple program when windows start but I don't want to show the console output window associated with that program. Just to test, the program can be as simple as:

    int main (int argc, char** argv)
    {
        while (1)
        {
             printf ("hello world...\n");
             Sleep (10000);
        }
    return 0;
    }

编译它为： CL foo.c的

我知道如何启动Windows启动时（投入启动文件夹，创建注册表等）的计划，但我不知道如何隐藏程序启动时自带控制台输出窗口。

I know how to start the program when windows is starting (putting in startup folder, creating registry etc), but I don't know how to hide the console output window that comes when the program is started.

在寻找这一点，我发现我可以用启动/ B foo.exe的。是否有这样做的任何其他方法？有些东西像＆放大器;我们在Unix上使用

While searching for this, I found that I can use start /B foo.exe. Is there any other method for doing this? some thing like "&" we use on unix.

我的实际的程序是大，是写在 C ，所以我不能用一些其他办法，我发现了 C＃（就像WinMain函数）和的Java （如解释<一个href=\"http://stackoverflow.com/questions/6065618/how-start-a-window-with-main-in-console-project\">here).

My actual program is big and is written in C, so I can not use some other alternatives i found for c# (like WinMain) and java (like explained here).

推荐答案

WinMain函数是不是C＃的切入点。 C＃中使用静态类的方法;它被称为默认主，但是可以被配置为任何静态类方法

WinMain is not a C# entry point. C# uses a method of a static class; it is called Main by default, but can be configured to any static-class method.

在Windows中，非控制台C程序应该定义的WinMain。然后，您可以使用链接程序的 /子系统链接它们：窗户命令行选项，可调用直接或从CL

In Windows, non-console C programs should define a WinMain. You can then link them using the linker's /subsystem:windows command-line option, invokable either directly or from CL.

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