相同的字符串，从VB.net和PHP获得不同的SHA1哈希值 [英] Same string, different SHA1 hash values obtained from VB.net and PHP

问题描述

我有一些问题字符串的SHA1哈希值。我试图从写在VB.net到PHP编写的服务器的客户端发送一个文件。我的问题是，当我通过相同的字符串来VB.net和PHP，由VB.net计算的SHA1值是由PHP计算出的值完全不同。

例如，我要带code为Base64字符串，然后计算Base64编码字符串的SHA1哈希。当计算机从vb.net版和PHP版本执行这个任务，我得到两个不同的SHA1值，即使显然为Base64 EN codeD字符串是相同的：

VB.net： 2E97A53B09C482A831540B532845BCAC79BFACCF
PHP： 350A2080264E2724D4BCBC521C35264D264A1DAF

我肯定失去了一些东西，你可以点我在正确的方向，告诉我我在做什么错在这里？

非常感谢你。

下面是VB.net code：

 昏暗cInput作为字符串
昏暗cBase64作为字符串
昏暗objSHA1作为新SHA1CryptoServiceProvider（）
昏暗abBytesToHash（）为字节
昏暗cHash作为字符串
cInput =快速的棕色狐狸跳过懒狗
cBase64 = Convert.ToBase64String（System.Text.Encoding.UTF8.GetBytes（cInput））abBytesToHash = System.Text.Encoding.ASCII.GetBytes（cBase64）abBytesToHash = objSHA1.ComputeHash（abBytesToHash）
cHash = BitConverter.ToString（objSHA1.ComputeHash（abBytesToHash））
cHash =替换（cHash， - ，）MSGBOX（BASE64：+ cBase64 + vbNewLine +SHA1：+ cHash）结果是：
BASE64：dGhlIHF1aWNrIGJyb3duIGZveCBqdW1wcyBvdmVyIHRoZSBsYXp5IGRvZw ==
SHA1：2E97A53B09C482A831540B532845BCAC79BFACCF
 

和这里的PHP code：

  $ cInput =快速的棕色狐狸跳过懒狗
$ cBase64 = base64_en code（$ cInput）;回波（BASE64：$ cBase64＆所述峰; br /＆gt;中SHA1：。strtoupper（SHA1（$ cBase64）））;//结果是：
// BASE64：dGhlIHF1aWNrIGJyb3duIGZveCBqdW1wcyBvdmVyIHRoZSBsYXp5IGRvZw ==
// SHA1：350A2080264E2724D4BCBC521C35264D264A1DAF
 

解决方案

那么，问题是，你在PHP .NET，也是唯一一个散列双散列。下面是你在.NET做翻译成PHP：

  $ cInput =快速的棕色狐狸跳过懒狗
$ cBase64 = base64_en code（$ cInput）;$ SHA = SHA1（$ cBase64，真正的）; //真正的参数返回原始字节而不是十六进制
$ chash = SHA1（$ SHA）;
 

所以你是双散列它。要修复它，你只需要你的算法更改为：

  cInput =快速的棕色狐狸跳过懒狗
cBase64 = Convert.ToBase64String（System.Text.Encoding.UTF8.GetBytes（cInput））abBytesToHash = System.Text.Encoding.ASCII.GetBytes（cBase64）cHash = BitConverter.ToString（objSHA1.ComputeHash（abBytesToHash））
cHash =替换（cHash， - ，）
 

请注意，我所做的只是删除 abBytesToHash = objSHA1.ComputeHash（abBytesToHash）行...

另外，你可以改变PHP来做到这一点：

  $ cInput =快速的棕色狐狸跳过懒狗
$ cBase64 = base64_en code（$ cInput）;回声BASE64。 $ cBase64。 ＆LT; BR /＆gt;中;
回声SHA1。 strtoupper（SHA1（SHA1（$ cBase64，真）））;
 

I have some problems with the SHA1 hash value of a string. I'm trying to send a file from a client written in VB.net to a server written in PHP. My problem is that when I pass the same string to VB.net and PHP, the SHA1 value calculated by VB.net is completely different from the value calculated by PHP.

For example, I want to encode a string in Base64 and then calculate the SHA1 Hash of the Base64 string. When the computer executes this task from the vb.net version and from the PHP version I get two different SHA1 values, even if apparently the Base64 encoded string is the same:

VB.net: 2E97A53B09C482A831540B532845BCAC79BFACCF PHP: 350A2080264E2724D4BCBC521C35264D264A1DAF

I'm surely missing something, could you point me in the right direction and tell me what I'm doing wrong here?

Thank you very much

Here's the VB.net Code:

Dim cInput As String
Dim cBase64 As String
Dim objSHA1 As New SHA1CryptoServiceProvider()
Dim abBytesToHash() As Byte
Dim cHash As String


cInput = "the quick brown fox jumps over the lazy dog"
cBase64 = Convert.ToBase64String(System.Text.Encoding.UTF8.GetBytes(cInput))

abBytesToHash = System.Text.Encoding.ASCII.GetBytes(cBase64)

abBytesToHash = objSHA1.ComputeHash(abBytesToHash)
cHash = BitConverter.ToString(objSHA1.ComputeHash(abBytesToHash))
cHash = Replace(cHash, "-", "")

MsgBox("BASE64: " + cBase64 + vbNewLine + "SHA1: " + cHash)

' Result is:
' BASE64: dGhlIHF1aWNrIGJyb3duIGZveCBqdW1wcyBvdmVyIHRoZSBsYXp5IGRvZw==
' SHA1: 2E97A53B09C482A831540B532845BCAC79BFACCF

And here's the PHP Code:

$cInput = "the quick brown fox jumps over the lazy dog";
$cBase64 = base64_encode($cInput);

echo("BASE64: " . $cBase64 . "<br />" . "SHA1: " . strtoupper(sha1($cBase64)));

// Result is:
// BASE64: dGhlIHF1aWNrIGJyb3duIGZveCBqdW1wcyBvdmVyIHRoZSBsYXp5IGRvZw==
// SHA1: 350A2080264E2724D4BCBC521C35264D264A1DAF

解决方案

Well, the problem is that you're double hashing in .NET and only single hashing in PHP. Here's what you're doing in .NET translated into PHP:

$cInput = "the quick brown fox jumps over the lazy dog";
$cBase64 = base64_encode($cInput);

$sha = sha1($cBase64, true); // The true param returns the raw bytes instead of hex
$chash = sha1($sha);

So you're double hashing it. To fix it, you just need to change your algorithm to:

cInput = "the quick brown fox jumps over the lazy dog"
cBase64 = Convert.ToBase64String(System.Text.Encoding.UTF8.GetBytes(cInput))

abBytesToHash = System.Text.Encoding.ASCII.GetBytes(cBase64)

cHash = BitConverter.ToString(objSHA1.ComputeHash(abBytesToHash))
cHash = Replace(cHash, "-", "")

Note that all I did was remove the abBytesToHash = objSHA1.ComputeHash(abBytesToHash) line...

Alternatively, you could change the PHP to do this:

$cInput = "the quick brown fox jumps over the lazy dog";
$cBase64 = base64_encode($cInput);

echo "BASE64: " . $cBase64 . "<br />";
echo "SHA1: " . strtoupper(sha1(sha1($cBase64, true)));

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