如何设置等于从bash中的一种命令的输出变量? [英] How to set a variable equal to the output from a command in Bash?
问题描述
我工作的一个简单的脚本项目的工作,涉及到使用猛砸。我有一个pretty简单的脚本,是类似如下:
I am working on a simple scripting project for work that involves the use of Bash. I have a pretty simple script that is something like the following:
#!/bin/bash
VAR1="$1"
VAR2="$2"
MOREF='sudo run command against $VAR1 | grep name | cut -c7-'
echo $MOREF
当我运行在命令行这个脚本并传递给它的参数,我没有得到任何输出。然而,当我运行中包含 $ MOREF
变量的命令,我能够得到的输出。我想知道如何能够采取必须在脚本中运行一个命令的结果,将其保存到一个变量,然后输出在屏幕上的变量?
When I run this script from the command line and pass it the arguments, I am not getting any output. However, when I run the commands contained within the $MOREF
variable, I am able to get output. I would like to know how one can take the results of a command that needs to be run within a script, save it to a variable, and then output that variable on the screen?
推荐答案
在除反引号,你可以使用 $()
,我觉得这更容易阅读,并允许嵌套。
In addition to the backticks, you can use $()
, which I find easier to read, and allows for nesting.
OUTPUT="$(ls -1)"
echo "${OUTPUT}"
引用()做此事preserve多行的值。
Quoting ("
) does matter to preserve multi-line values.
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