猛砸，Linux的，需要根据从另一个文件匹配的内容从一个文件中删除行 [英] Bash, Linux, Need to remove lines from one file based on matching content from another file

问题描述

有关于如何当另一个文件存在相同的行删除一个文件行的例子很多。我已经通过他们读，他们都删除，如果全系列匹配。类似的例子：的grep -vxF -f文件1文件2

我有略有不同。我从我的网站和我的客户网站的URL列表。我希望当域在另一个文件中的域相匹配，以消除从该文件中的行。

因此​​，第一个文件可能如下：

  http://www.site1.com/some/path
http://www.site2.com/some/path
http://www.site3.com/some/path
http://www.site4.com/some/path
 

第二个文件可以是：

  site2.com
www.site4.com
 

我想输出是：

  http://www.site1.com/some/path
http://www.site3.com/some/path
 

解决方案

您有太多的的grep 标志。具体做法是： -x 将让你从得到你想要的结果。

假设的文件1 的有图案，和文件2 的有网址，只需使用：

 的grep -v -f文件1文件2
 

的 -x 标志将让你找不到你想要的结果：使用 -x 表示：比赛只对整条生产线，即只如果行是完全匹配的线路，例如：的 site2.com 的

在的grep人：

  

-x，--line，正则表达式

  
  

选择只有那些比赛，整个线路完全匹配。

There are many examples on how to remove lines in one file when that same line exists in another file. I have read through them and they all remove if the full line matches. Examples like: grep -vxF -f file1 file2

What I have is slightly different. I have a list of URLs from my websites and my clients websites. I want to remove lines from that file when the domain matches a domain in another file.

So the first file might look like:

http://www.site1.com/some/path
http://www.site2.com/some/path
http://www.site3.com/some/path
http://www.site4.com/some/path

The second file could be:

site2.com
www.site4.com

I would like the output to be:

http://www.site1.com/some/path
http://www.site3.com/some/path

解决方案

You have too many grep flags. Specifically: -x will keep you from getting your desired results.

Assuming that file1 has the patterns, and file2 has the URLs, just use:

grep -v -f file1 file2

The -x flag will keep you from getting the results that you want: using -x means: match only against the entire line, i.e. only match a line if the line is exactly, e.g. site2.com.

From the man grep:

-x, --line-regexp

Select only those matches that exactly match the whole line.

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