使用找到-exec {}，是有办法的总数？ [英] Using find with -exec {}, is there a way to count the total?

问题描述

我使用类似这样的命令：

I am using a command similar to this one:

find . -name "*.php" -exec chmod 755 {} \;

虽然，我没有使用chmod，我使用的是不同的命令，我不会在这里列出。此命令工作正常。但是，也有成千上万的文件和目录来进行操作，并且该操作需要花费一些时间。我想知道，如果有显示某种共有当操作完成的方法吗？也许是修改过的文件的计数？

Although, I am not using chmod, I am using a different command which I will not list here. This command is working fine. However, there are thousands of files and directories to be operated on, and this operation takes some time. I am wondering if there is a way to display some sort of total when the operation is complete? Perhaps a count of modified files?

我能想到的唯一的事情很简单，就是做这样的事情：

The only thing I can think of is simply to do something like:

find . -name "*.php" -exec chmod 755; echo "+"; {} \;

请问这项工作？至少我们可以看到，事情正在发生...任何人有更好的建议？

Will that work? At least we can see that something is happening... Anyone have a better suggestion?

推荐答案

这个作品：

$ find . -name "*.php" -exec chmod 755 {} \; -exec /bin/echo {} \; | wc -l

您必须包括第二 -exec /斌/回声这个工作。如果找到命令没有输出，则厕所没有输入计数线。

You have to include a second -exec /bin/echo for this to work. If the find command has no output, then wc has no input to count lines for.

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