排序日志文件通过在Linux命令行的时间戳 [英] sort logfile by timestamp on linux command line

问题描述

我有类似条目的日志文件：

I have a logfile with entries like:

...    
freeswitch.log:2011-09-08 12:21:07.282236 [ERR] ftdm_queue.c:136 Failed to enqueue obj 0x7f2cda3525c0 in queue 0x7f2ce8005990, no more room! windex == rindex == 58!
freeswitch.log:2011-08-08 13:21:07.514261 [ERR] ftdm_queue.c:136 Failed to enqueue obj 0x7f2cda354460 in queue 0x7f2ce8005990, no more room! windex == rindex == 58!
freeswitch.log:2011-06-04 16:21:08.998227 [ERR] ftdm_queue.c:136 Failed to enqueue obj 0x7f2cda356300 in queue 0x7f2ce8005990, no more room! windex == rindex == 58! 
freeswitch.log:2011-09-08 12:21:10.374238 [ERR] ftdm_queue.c:136 Failed to enqueue obj 0x7f2cda3581a0 in queue 0x7f2ce8005990, no more room! windex == rindex == 58!
...

我如何才能通过每一行中decending时间戳使用Linux命令行工具的文件进行排序？

How can I sort the file with linux command line tools by the timestamp in each row decending?

推荐答案

使用排序的-k标志：

sort -k1 -r freeswitch.log

这将排序的文件，在倒车时，由所述第一密钥（即freeswitch.log：2011-09-08 12：21：07.282236）。如果文件名总是相同（freeswitch.log），那么它应该通过的日期进行排序。

That will sort the file, in reverse, by the first key (i.e. freeswitch.log:2011-09-08 12:21:07.282236). If the filename is always the same (freeswitch.log), then it should sort by the date.

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