无法设置变量case语句庆典 [英] unable to set variable in case statement bash

问题描述

我想设置的基础上一堆的输入条件的变量。这里的code的小样本：

 ＃！/斌/庆典
INSTANCE_SIZE =
案$ 1
   微）
     $ INSTANCE_SIZE =t1.micro
     ;;
   小）
     $ INSTANCE_SIZE =的m1.small     ;;
ESAC
回声$ INSTANCE_SIZE
 

当我运行与-ex开关脚本，并指定适当的参数：

  +案例$ 1
+ =的m1.small
./provision：第19行：=的m1.small：命令未找到
 

解决方案

您需要删除该任务的 $ 标志 - INSTANCE_SIZE =的m1.small。随着美元符号， $ INSTANCE_SIZE 被其取代的价值，也没有转让发生 - bash而尝试执行是由于插值命令

I'm trying to set a variable based on a bunch of input conditions. Here's a small sample of the code:

#!/bin/bash
INSTANCE_SIZE=""
case "$1" in
   "micro")
     $INSTANCE_SIZE="t1.micro"
     ;;
   "small")
     $INSTANCE_SIZE="m1.small"

     ;;
esac
echo $INSTANCE_SIZE

When I run the script with the -ex switch and specify the proper argument:

+ case "$1" in
+ =m1.small
./provision: line 19: =m1.small: command not found

解决方案

You need to remove the $ sign in the assignments - INSTANCE_SIZE="m1.small". With the dollar sign, $INSTANCE_SIZE gets substituted with its value and no assignment takes place - bash rather tries to execute the command that resulted from the interpolation.

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