有什么不对我的UNIX脚本 [英] what is wrong with my unix script

问题描述

#!/bin/bash

while echo -n "Player's name?"
    read name
    [ $name != 'ZZZ' ]
do
    searchresult=$(grep [$name] playername)
    if [ $searchresult = 0 ]
    then
        echo -n "if See target (T/t) or team name (M/m)?"
        while [ [ $target!="T" ] || [ $team!="M" ] ]

            read team
            read target

            do
                echo "Please enter only T or M."
            done
            if $target="T"
            then
                grep [ $name ] targetselected
            else
                grep [ $name ] teamselected
            fi

    else
        echo 'no such player'
    fi

done
echo You are now exited search

运行时错误说

10号线 - 如果[$ SearchResult中= 0];有这么多的争论，

line 10 - if [ $searchresult = 0 ] ; have so many arguments,

是什么意思呢？我该如何解决？

what is that mean? how can i fix it?

推荐答案

引用变量名：

"$searchresult"

此外，有啊有脚本等故障。

Also, youa have other failures in the script.

• 从里grep删除括号，如果你不需要他们


• 重写条件，而

这篇关于有什么不对我的UNIX脚本的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！