如何捕捉Python的subprocess.check_output异常输出（）？ [英] How to catch exception output from Python subprocess.check_output()?

问题描述

我试图从Python中做一个比特币付款。在bash我通常会做到这一点：

I'm trying to do a Bitcoin payment from within Python. In bash I would normally do this:

bitcoin sendtoaddress <bitcoin address> <amount>

因此​​，例如：

so for example:

bitcoin sendtoaddress 1HoCUcbK9RbVnuaGQwiyaJGGAG6xrTPC9y 1.4214

如果是全成我得到的事务id作为输出，但如果我尝试比我的比特币余额转移的量时，我得到以下的输出：

if it is successfull I get a transaction id as output but if I try to transfer an amount larger than my bitcoin balance, I get the following output:

error: {"code":-4,"message":"Insufficient funds"}

在我的Python程序我现在尝试做支付如下：

In my Python program I now try to do the payment as follows:

import subprocess

try:
    output = subprocess.check_output(['bitcoin', 'sendtoaddress', address, str(amount)])
except:
    print "Unexpected error:", sys.exc_info()

如果有足够的余额它工作正常，但如果没有足够的余额 sys.exc_info（）打印出这样的：

If there's enough balance it works fine, but if there's not enough balance sys.exc_info() prints out this:

(<class 'subprocess.CalledProcessError'>, CalledProcessError(), <traceback object at 0x7f339599ac68>)

这不包括我在命令行中得到尽管错误。所以我的问题是;从内部的Python

It doesn't include the error which I get on the command line though. So my question is; how can I get the outputted error ({"code":-4,"message":"Insufficient funds"}) from within Python?

所有的提示是欢迎！

推荐答案

按照<一个href=\"https://docs.python.org/2/library/subprocess.html#subprocess.check_output\"><$c$c>subprocess.check_output()文档上的错误引发的异常有一个输出属性，你可以用它来访问错误的详细信息：

According to the subprocess.check_output() docs, the exception raised on error has an output attribute that you can use to access the error details:

try:
    subprocess.check_output(...)
except subprocess.CalledProcessError as e:
    print e.output

然后，您应该能够分析这个字符串，并与 JSON 模块解析错误的详细信息：

You should then be able to analyse this string and parse the error details with the json module:

if e.output.startswith('error: {'):
    error = json.loads(e.output[7:]) # Skip "error: "
    print error['code']
    print error['message']

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