的init.d脚本挂 [英] Init.d script hanging
问题描述
我有一个剧本的init.d，看起来像：
I have an init.d script that looks like:
#!/bin/bash
# chkconfig 345 85 60
# description: startup script for swapi
# processname: swapi
LDIR=/var/www/html/private/daemon
EXEC=swapi.php
PIDF=/var/run/swapi.pid
IEXE=/etc/init.d/swapi
### BEGIN INIT INFO
# Provides: swapi
# Required-Start: $local_fs
# Required-Stop:
# Default-Start: 3 4 5
# Default-Stop: 0 1 2 6
# Short-Description: startup script for swapi
# Description: startup script for swapi.php which processes actionq into switch
### END INIT INFO
if [ ! -f $LDIR/$EXEC ]
then
echo "swapi was not found at $LDIR/$EXEC"
exit
fi
case "$1" in
start)
if [ -f $PIDF ]
then
echo "swapi is currently running. Killing running process..."
$IEXE stop
fi
$LDIR/$EXEC >> $LDIR/swapi.log & MYPID=$!
echo $MYPID > $PIDF
echo "swapi is now running."
;;
stop)
if [ -f $PIDF ]
then
echo "Stopping swapi."
PID_2=`cat $PIDF`
if [ ! -z "`ps -f -p $PID_2 | grep -v grep | grep 'swapi'`" ]
then
kill -9 $PID_2
fi
rm -f $PIDF
else
echo "swapi is not running, cannot stop it. Aborting now..."
fi
;;
force-reload|restart)
$0 stop
$0 start
;;
*)
echo "Use: /etc/init.d/swapi {start|stop|restart|force-reload}"
exit 1
esac
然后，我有一个存活的cronjob调用此如果PID下降。问题是，保活脚本挂起，每当我运行它像一个cron作业（即运行部分的/ var / www / html等/私营/ fivemin），（保活脚本在/ var / WWW是/ HTML /私营/ fivemin）
And then I have a keepalive cronjob that calls this if the pid goes down. Problem is that that keepalive script hangs whenever I run it like a cron job (ie. run-parts /var/www/html/private/fivemin), (the keepalive script being in /var/www/html/private/fivemin).
有没有在我的init.d脚本的东西时髦，我很想念？
Is there something funky in my init.d script that I am missing?
我一直在货架我的大脑在这个问题上几个小时吧！我在centos4 BTW。
I have been racking my brain on this problem for hours now! I am on centos4 btw.
感谢您的帮助。
-Eric
Thanks for any help. -Eric
编辑：
保活/的cronjob脚本简化测试，以一个简单的：
The keepalive/cronjob script was simplified for testing to a simple:
#!/usr/bin/php
<?
exec("/etc/init.d/swapi start");
?>
奇怪，这是从swapi.php输出误差投入相似，但我所有的输出被丢到了的init.d脚本swapi.log正常的cron输出的/ var / spool / mail中？
The strange this is the error output from swapi.php is put into /var/spool/mail like normal cron output except that I have all the output being dumped into the swapi.log in the init.d script?
当我从CLI运行keepalive.php（从/根），它的运作完全按照我希望它。
When I run keepalive.php from the cli (as root from /) it operates exactly as I would expect it to.
在运行保活的ps aux | grep的PHP是这样的：
When keepalive runs ps aux | grep php looks like:
root 4525 0.0 0.0 5416 584 ? S 15:10 0:00 awk -v progname=/var/www/html/private/fivemin/keepalive.php progname {????? print progname ":\n"????? progname="";???? }???? { print; }
root 4527 0.7 1.4 65184 14264 ? S 15:10 0:00 /usr/bin/php /var/www/html/private/daemon/swapi.php
如果我做了：
/etc/init.d/swapi stop
从CLI那么两个程序都不再列出。
from the cli then both programs are no longer listed.
Swapi ls -l命令如下：
Swapi ls -l looks like:
-rwxr-xr-x 1 5500 5500 33148 Aug 29 15:07 swapi.php
下面是crontab的样子：
Here is what the crontab looks like:
*/5 * * * * root run-parts /var/www/html/private/fivemin
下面是swapi.php的第一个比特
Here is the first bit of swapi.php
#!/usr/bin/php
<?
chdir(dirname( __FILE__ ));
include("../../config/db.php");
include("../../config/sql.php");
include("../../config/config.php");
include("config_local.php");
include("../../config/msg.php");
include("../../include/functions.php");
set_time_limit(0);
echo "starting @ ".date("Ymd.Gi")."...\n";
$actionstr = "";
while(TRUE){
我修改剧本的init.d，把上面的初始化变量声明，它并没有发挥作用。
I modified the init.d script and put init above the variable declarations, it did not make a difference.
推荐答案
答案是，庆典住打开，因为我的init.d脚本不是重定向stderr输出。我现在已经改成了
The answer was that bash was staying open because my init.d script was not redirecting the stderr output. I have now changed it to
$LDIR/$EXEC &> $LDIR/swapi.log & MYPID=$!
和现在的功能完好。
感谢大家的帮助！
这篇关于的init.d脚本挂的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
