像所有的命令行参数bash脚本存储到一个变量 [英] Like to store all command-line arguments to a bash script into a single variable

问题描述

让我们说我有一个叫bash脚本的 foo.sh

我想这样称呼它

  foo.sh这里的东西在命令行一堆
 

和我想它所有的文本存储到一个变量并打印出来。

所以，我的输出是：

 下面是在命令行一堆东西
 

我将如何做到这一点？

解决方案

 回声$ *
 

会做你想做的，即打印出完整的命令行参数，用空格隔开（或者，在技术上，无论 $ IFS 的值）。如果你想将它存储到一个变量，你可以做

  thevar =$ *
 

如果不回答你的问题不够好，我不知道该说些什么......

Let's say I have a bash script called foo.sh.

I'd like to call it like this

foo.sh Here is a bunch of stuff on the command-line

and I'd like it to store all of that text into a single variable and print it out.

So my output would be:

Here is a bunch of stuff on the command-line

How would I do this?

解决方案

echo "$*"

would do what you want, namely printing out the entire command-line arguments, separated by a space (or, technically, whatever the value of $IFS is). If you wanted to store it into a variable, you could do

thevar="$*"

If that doesn't answer your question well enough, I'm not sure what else to say...

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