Linux的巴什 - 日期格式 [英] Linux Bash - Date Format

问题描述

我的日期格式为YYYY-MM-DD-HH：MM：SS
如何检查我的投入？

My date format is yyyy-mm-dd-hh:mm:ss How do I check my input?

应该是这样的：

#!/bin/bash

read -p "Date (format yy-mm-dd-HH-MM-SS): " input

check=$(date +"%Y-%m-%d-%H:%M:%S")

if [ $input -eq $check ]; do

     echo "Right!"

else
     echo "False!"

fi

但是，这并不检查日期是我比较投入与实际日期。

But that doesn't check the date It compares my input with the real date.

祝商祺
文斯

推荐答案

另见（更强的方法）

尝试：

#!/bin/bash

read -p "Date (format yyyy-mm-dd): " input
check=$(date +%F)

if [ "$input" == "$check" ]; then
    echo "Right!"
else
    echo "False!"
fi

或

#!/bin/bash

read -p "Date (format YYYY-MN-DD-HH24:MM:SS): " input
check=$(date +%F-%T)

if [ "$input" == "$check" ]; then
    echo "Right!"
else
    echo "False!"
fi

很好的测试：

cat >hesdate.sh     # Copy 1st sample and paste to terminal
chmod +x hesdate.sh
date +%F ; ./hesdate.sh
2013-01-04
Date (format yyyy-mm-dd): 2013-01-04
Right!

cat >hesdate.sh     # Copy 2nd sample and paste to terminal
date -d now\ +10\ sec +%F-%T ; ./hesdate.sh 
2013-01-04-10:17:06                                       # copy this line
Date (format YYYY-MN-DD-HH24:MM:SS): 2013-01-04-10:17:06  # past exactly 10 secs after
Right!

修改添加

有关测试的日期，你可以：

For testing a date, you could:

[[ $input =~ ^[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9]$ ]]

if [[ $input =~ ^2012-[0-9][0-9]-[0-9][0-9]-[0-9][0-9]:[0-9][0-9]:[0-9][0-9]$ ]];then

和/或

inputSecs=$(date -d "${input%-*} ${input##*-}" +%s)

使用引导方法，让您确认的格式的和 输入可靠性的

如果您要检查输入，还有一个更精细的方式：

If you want to check input, there is a finer method:

unset adate
declare -A adate
date=2013-12-04-10:17:06
for field in s:0-59 m:0-59 h-0-23 D-1-31 M-1-12 Y#2000-2100 ;do
   sep=${field:1:1} min=${field:2} field=${field:0:1} max=${min#*-} min=${min%-*}
   crt=${date##*${sep:-#}}
   ((min<=10#$crt&&10#$crt<=max)) && adate[$field]=$crt ||
       echo Error: $crt not between $min and $max in $field field.
   date=${date%$sep*}
 done
declare -p adate

这将转储 ADATE 数组变量：

declare -A adate='([D]="04" [M]="12" [Y]="2013" [h]="10" [m]="17" [s]="06" )'

从那里，你可以重新验证的天数的：

max=$(date -d "${adate[Y]}-${adate[M]}-1 +1 month -1 day" +%d)
((10#${adate[D]}>max)) && echo "Error Day number too high: (${adate[D]}>$max)."

唯一没有测试有字段长度，如果

The only thing not tested there is field length if

date=2012-02-29-10:17:06

将工作，然后

date=2012-2-29-10:17:06

将工作过（只有一个在一天的实地位）。

will work too (there is only one digit in day field).

如果需要，你可以改变行：

If needed, you could change the line:

for field in s:0-59 m:0-59 h-0-23 D-1-31 M-1-12 Y#2000-2100 ;do
sep=${field:1:1} min=${field:2} field=${field:0:1} max=${min#*-} min=${min%-*}
crt=${date##*${sep:-#}}

为

for field in s:20-59 m:20-59 h-20-23 D-21-31 M-21-12 Y#42000-2100 ;do
sep=${field:1:1} len=${field:2:1} min=${field:3} field=${field:0:1} max=${min#*-} min=${min%-*}
crt=${date##*${sep:-#}}
[ ${#crt} -eq $len ] || echo "Error: Field $field is no $len len: ${#crt}."

诺塔：新年场2000和2100之间的任意限制，但是这是很容易理解/更改

Nota: Year field is arbitrarily limited between 2000 and 2100, but this is easy to understand/change.

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