线==＆QUOT后删除文件的内容; XXXXXXX＆QUOT; [英] Delete file contents after line == "xxxxxxx"

问题描述

我有一堆我需要清理的文件。我需要删除线等于什么（该行也应该被删除）。

I have a bunch of files I need to clean. I need to delete all lines below a line that is equal to something (that line should be removed too).

如何能做到这一点在bash？

How can I do that in bash?

我只需要怎样删除线的例子，我可以循环所有的文件我自己。

I just need the example of how to delete the lines, I can loop all the files myself.

推荐答案

简单的方法就是告诉SED当它看到其退出。

Easiest to just tell sed to quit when it sees it.

sed -n '/xxxxxxx/q;p' input.txt

这篇关于线==＆QUOT后删除文件的内容; XXXXXXX＆QUOT;的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！