我怎样写一个Unix脚本统计一个文件评语数量？ [英] How do I write a Unix script which counts the number of reviews in a file?

问题描述

我有许多均含有一酒店的评价文件的，我想编写一个脚本，可计算每档评语数量。一个文件名的一个例子是 hotel_73757 。在每个文件的文本布局如下：

I have a number of files which each contain reviews of a hotel and I would like to write a script which counts the number of reviews per file. An example of one file name would be hotel_73757. The text in each file is laid out as follows:

<Overall Rating>3.5
<Avg. Price>$260
<URL>http://www.tripadvisor.com/ShowUserReviews-g31310-d73757-r23009196-Wyndham_Phoenix-Phoenix_Arizona.html

<Author>TexasSharvi
<Content>the new updo is ... it's great! 
<Date>Dec 26, 2008
<No. Reader>-1
<No. Helpful>-1
<Overall>4
<Value>4
<Rooms>4
<Location>4
<Cleanliness>5
<Check in / front desk>5
<Service>-1
<Business service>4

<Author>ChrisLongo
<Content>Just Dirty... Will never stay at any Wyndham hotel again. 
<Date>Dec 24, 2008
<No. Reader>1
<No. Helpful>1
<Overall>1
<Value>1
<Rooms>1
<Location>1
<Cleanliness>1
<Check in / front desk>1
<Service>1
<Business service>-1

这则每次审查之间一行空白重复，每个评审都有相同的字段。我想检查的时候作者的数量出现在每个文件将这项工作？在此先感谢

This then repeats with a single line gap between each review, every review has the same fields. I was thinking of checking the number of times "Author" appears in each file would this work? Thanks in advance

推荐答案

只需使用

grep -c "Author" yourFile

如果你真的想这样一个脚本：

If you really want to make a script of this:

#!/bin/bash
################################################################################
# countreviews.sh
# Counts the number of times the word "<Author>" appears in the specified file.
################################################################################
grep -c "^<Author>" "$1"

请其可执行文件：

chmod +x countreviews.sh

和与运行：

./countreviews.sh file

或

./countreviews.sh "file with space in name"

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