我每次脚本输出之前打印出一份声明 [英] Print out a statement before each output of my script

问题描述

我有一个脚本来检查单词作者文件夹中的每个文件，然后打印出的次数，每个文件一行，为了从最高到最低。在总我有825文件。一个例子输出是

I have a script that checks each file in a folder for the word "Author" and then prints out the number of times, one line per file, in order from highest to lowest. In total I have 825 files. An example output would be

53
22
17

我想使它这样我在每条线上的数字之前打印出来的东西。这将是以下 hotel_ $ I 所以上面的例子现在是：

I want to make it so that I print out something before each number on every line. This will be the following hotel_$i so the above example would now be:

hotel_1 53
hotel_2 22
hotel_3 17

我试图在我的shell脚本使用for循环这样做：

I have tried doing this using a for loop in my shell script:

for i in {1..825}
do
    echo "hotel_$i"
    find . -type f -exec bash -c 'grep -wo "Author" {} | wc -l' \; | sort -nr
done

但基本上打印出 hotel_1 ，然后进行搜索和排序的所有825文件，那么 hotel_2 重复搜索和分类等。我如何让这个它的每一个输出前打印？

but this basically prints out hotel_1, then does the search and sort for all 825 files, then hotel_2 repeats the search and sort and so on. How do I make it so that it prints before every output?

推荐答案

您可以使用粘贴命令，它结合了不同的文件行：

You can use the paste command, which combines lines from different files:

paste <(printf 'hotel_%d\n' {1..825}) \
<(find . -type f -exec bash -c 'grep -wo "Author" {} | wc -l' \; | sort -nr)

（只是把这个两行的可读性，可以是一个班轮没有 \\ ）

这收割机粘贴与进程替换，使得指挥模样的文件（命名管道）的输出粘贴。

This combines paste with process substitution, making the output of a command look like a file (a named pipe) to paste.

第一个命令打印 hotel_1 ， hotel_2 在单独的行等各，第二个命令是你的找到命令。

The first command prints hotel_1, hotel_2 etc. on a separate line each, and the second command is your find command.

有关短期输入文件，输出看起来是这样的：

For short input files, the output looks like this:

hotel_1 7
hotel_2 6
hotel_3 4
hotel_4 3
hotel_5 3
hotel_6 2
hotel_7 1
hotel_8 0
hotel_9 0

这篇关于我每次脚本输出之前打印出一份声明的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！