'pretty打印“窗口％PATH％变量 - 如何分割上”;“在CMD壳 [英] 'Pretty print' windows %PATH% variable - how to split on ';' in CMD shell

问题描述

我想运行在Windows CMD提示一个简单的一行打印我的％PATH％变量，每行一个条目。

我试过这样： FOR / Fdelims =;在（％PATH％）％一做回声％A 但这只是打印的第一项：

  Z：\\＆GT; FOR / Fdelims =;在（％PATH％）做回声％A％一Z：\\＆GT;回声C：\\ python25 \\。
C：\\ python25 \\。
 

另外，你可以从上面的输出看，这也是印刷回声％，A 命令以及输出。有没有什么办法阻止呢？

如果我尝试了类似的命令，我让所有的条目，但仍获得了回声％，A 输出垃圾邮件的结果。我不明白为什么以下打印所有条目，但我对％PATH％的尝试没有。我怀疑我不明白/ F开关。

  Z：\\＆GT;在（1 2 3）做回声％A％一Z：\\＆GT;回声1
1Z：\\＆GT;回声2
2Z：\\＆GT;回声3
3
 

解决方案

最简单的方法是使用

 在一个％（％路径：=，％）做@echo％〜一
 

这适用于所有无; 路径和无在一个单一的元素结果
C：\\ QT \\ 4.6.3 \\ BIN：\\ Program Files文件; C：与路径= C测试的\\文件和放大器;设置

但是，一个永远解决方案是一个有点复杂结果
修改：现在工作的变种

 关闭@echo
SETLOCAL DisableDelayedExpansion
设置VAR =富＆放大器;酒吧;巴兹＆LT;＆GT;珏;半;冒号; ^＆安培;嵌入式再富;！掷（中）一些（括号内）;无与伦比;-)（太设置VAR =％变种：=，％
设置VAR =％VAR：^ = ^^％
设置VAR =％VAR：放大器; = ^＆安培;％
设置VAR =％VAR：| = ^ |％
设置VAR =％变种：其中= ^＆下;％
设置VAR =％VAR：＆GT; = ^＆GT;％设置VAR =％VAR：= ^，^;％
REM **这是重点线，缺少的报价意
组VAR =％VAR：=％
设置VAR =％变种：=，％设置VAR =％VAR：;; =;％
设置VAR =％VAR：^; ^ =;％
设置VAR =％VAR：=％
设置VAR =％变种：=，％
设置VAR =％变种：，=，％
设置VAR =％VAR：=％SETLOCAL EnableDelayedExpansion
对于一个%%的（！VAR！）做（
    ENDLOCAL
    呼应%%〜一
    SETLOCAL EnableDelayedExpansion
）
 

我到底做了什么呢？结果
我试图要解决的主要问题，即引号内的分号应被忽略，只有的正常的分号应改为，

我用的是批间preTER本身来解决这个我。结果
首先，我必须使该字符串的安全的，转义所有特殊字符。结果
然后，所有';'被替换为 ^; ^; ，然后招开始在该行组VAR =％VAR：=，％（缺少的报价是关键！）。结果
这扩大的方式，所有的转义字符都失去了他们的逃命插入符号结果
VAR =富＆安培;酒吧;;巴兹＆LT;＆GT;珏;;半^; ^;冒号^; ^; ^＆安培;嵌入式！;;富再次;; ...结果
但是，只有外面的行情，所以现在有 ;; 和里面的 ^引号之外分号之间的差; ^; 。结果
这就是关键。

I want to run a simple one-liner in the Windows CMD prompt to print my %PATH% variable, one entry per line.

I tried this: for /f "delims=;" %a in ("%path%") do echo %a but this only prints the first entry:

Z:\>for /f "delims=;" %a in ("%path%") do echo %a

Z:\>echo c:\python25\.
c:\python25\.

Also as you can see from the output above, this is also printing the echo %a command as well as the output. Is there any way to stop this?

If I try a similar command, I get all the entries, but still get the echo %a output spamming the results. I don't understand why the following prints all entries, but my attempt on %PATH% doesn't. I suspect I don't understand the /F switch.

Z:\>for %a in (1 2 3) do echo %a

Z:\>echo 1
1

Z:\>echo 2
2

Z:\>echo 3
3

解决方案

The simple way is to use

for %a in ("%path:;=";"%") do @echo %~a

This works for all without ; in the path and without " around a single element
Tested with path=C:\qt\4.6.3\bin;C:\Program Files;C:\documents & Settings

But a "always" solution is a bit complicated
EDIT: Now a working variant

@echo off
setlocal DisableDelayedExpansion
set "var=foo & bar;baz<>gak;"semi;colons;^&embedded";foo again!;throw (in) some (parentheses);"unmatched ;-)";(too"

set "var=%var:"=""%"
set "var=%var:^=^^%"
set "var=%var:&=^&%"
set "var=%var:|=^|%"
set "var=%var:<=^<%"
set "var=%var:>=^>%"

set "var=%var:;=^;^;%"
rem ** This is the key line, the missing quote is intended
set var=%var:""="%
set "var=%var:"=""%"

set "var=%var:;;="";""%"
set "var=%var:^;^;=;%"
set "var=%var:""="%"
set "var=%var:"=""%"
set "var=%var:"";""=";"%"
set "var=%var:"""="%"

setlocal EnableDelayedExpansion
for %%a in ("!var!") do (
    endlocal
    echo %%~a
    setlocal EnableDelayedExpansion
)

What the hell I do there?
I try to solve the main problem, that the semicolons inside of quotes should be ignored, and only the normal semicolons should be replaced with ";"

I use the batch interpreter itself to solve this for me.
First I have to make the string safe, escaping all special characters.
Then all ';' are replaced with ^;^; and then the trick begins in the line set var=%var:"=""%" (The missing quote is the key!).
This expands in a way that all escaped characters are lose their escape caret
var=foo & bar;;baz<>gak;;"semi^;^;colons^;^;^&embedded";;foo again!;;...
But only outside of the quotes, so now there is a difference between semicolons outside of quotes ;; and inside ^;^;.
Thats the key.

这篇关于'pretty打印“窗口％PATH％变量 - 如何分割上”;“在CMD壳的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！