忽略批处理文件百分号 [英] Ignore percent sign in batch file

问题描述

我有一个从一个文件夹文件移动到另一个批处理文件。由另一个过程中产生的批处理文件。

I have a batch file which moves files from one folder to another. The batch file is generated by another process.

我的一些需要移动有字符串％20，在他们的文件：

Some of the files I need to move have the string "%20" in them:

move /y "\\myserver\myfolder\file%20name.txt" "\\myserver\otherfolder"

这失败，因为它试图找到与名称的文件：

This fails as it tries to find a file with the name:

\\myserver\myfolder\file0name.txt

有没有办法忽略％？我不能改变产生逃避这一点，文件等通过加倍百分号（ %% ），以逃避 / 或 ^ （尖），等等。

Is there any way to ignore %? I'm not able to alter the file generated to escape this, such as by doubling percent signs (%%), escaping with / or ^ (caret), etc.

推荐答案

您应该能够使用插入符号（^）<一个href=\"http://windowsitpro.com/article/articleid/39047/how-can-i-pass-a-percent-sign--value-to-regexe.html\"相对=nofollow>逃脱百分号。

You should be able to use a caret (^) to escape a percent sign.

究其原因％2 正在消失是该批处理文件替换第二个参数传入，和你似乎没有第二个参数。要解决这个问题的方法是实际尝试 foo.bat ^％^ 1％2 ... ，以便当％2 在命令中遇到，它实际上是与取代文字％2 。

The reason %2 is disappearing is that the batch file is substituting the second argument passed in, and your seem to not have a second argument. One way to work around that would be to actually try foo.bat ^%1 ^%2... so that when a %2 is encountered in a command, it is actually substituted with a literal %2.

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