如何从第N个位置的批处理文件的参数呢？ [英] how to get batch file parameters from Nth position on?

问题描述

继<一个href=\"http://stackoverflow.com/questions/26551/how-to-pass-command-line-parameters-in-batch-file\">How将命令行参数在批处理文件是怎么开始的其余参数与准确指定它们？我不想用SHIFT，因为我不知道有多少参数有可能是和想避免计数他们，如果我能。

Further to How to Pass Command Line Parameters in batch file how does one get the rest of the parameters with specifying them exactly? I don't want to use SHIFT because I don't know how many parameters there might be and would like to avoid counting them, if I can.

例如，鉴于此批处理文件：

For example, given this batch file:

@echo off
set par1=%1
set par2=%2
set par3=%3
set therest=%???
echo the script is %0
echo Parameter 1 is %par1%
echo Parameter 2 is %par2%
echo Parameter 3 is %par3%
echo and the rest are %therest%

运行 mybatch OPT1 OPT2 OPT3 OPT4 opt5 ... opt20 将产生：

the script is mybatch
Parameter 1 is opt1
Parameter 2 is opt2
Parameter 3 is opt3
and the rest are opt4 opt5 ...opt20

我知道％* 给出了所有的参数，但我不wan't前三（例如）。

I know %* gives all the parameters, but I don't wan't the first three (for example).

推荐答案

下面是你如何能做到这一点，而无需使用 SHIFT ：

Here's how you can do it without using SHIFT:

@echo off

for /f "tokens=1-3*" %%a in ("%*") do (
    set par1=%%a
    set par2=%%b
    set par3=%%c
    set therest=%%d
)

echo the script is %0
echo Parameter 1 is %par1%
echo Parameter 2 is %par2%
echo Parameter 3 is %par3%
echo and the rest are %therest%

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