删除所有文件夹，除了在Windows介绍最新2文件夹 [英] Delete all folders except 2 lastest folders in Windows

问题描述

我要删除从目录中的所有文件夹，除了最新的2个文件夹（最近更新日期）。我想通过一个小的命令行code做到这一点。我该怎么做？下面是code显示由最后修改时间排序的文件夹。

  DIR / AD-H / OD
 

我试着用 FOR / D 命令。

 为/ D跳过= 2令牌= *％中（DIR / AD-H / OD）G DO呼应要删除％G
 

不过，我得到了以下错误消息。

 跳过= 2令牌= *在这个时候意外。
 

我该怎么办呢？

解决方案

  FOR / F在（'DIR / B / AD-H跳过= 2 delims =％G / O -d'）DO回声要删除％G
 

FOR / F 从处理输出行单引号 DIR ...

Delims = 更好。 标记= * 将在这里工作，但SUP presses前导空格。

/ B 来燮preSS头输出 DIR

/ O-D 的反向日期顺序。你想保留两跳过迪尔斯，在反向日期排序发生的FIRS。

...好回声的安全措施。

I want to delete all the folders from a directory except the latest 2 folders (Last modified date). I want to do this by a small command line code. How do I do it? Below is the code to display folders sorted by last modified time.

dir /ad-h /od

I tried using FOR /D command.

for /d "skip=2 tokens=*" %G in ("dir /ad-h /od") DO echo going to delete %G

But I got the below error message.

"skip=2 tokens=*" was unexpected at this time.

How do I do it?

解决方案

for /f "skip=2 delims=" %G in ('dir /B /ad-h /o-d') DO echo going to delete %G

For /f to process lines of "output" from single-quoted DIR...

Delims= is better. tokens=* will work here, but suppresses leading spaces.

/b to suppress header output from dir

/o-d for REVERSE-date order. You want to KEEP the two skipped dirs, which occur FIRS in a reverse-date sort.

...good echo safety measure.

这篇关于删除所有文件夹，除了在Windows介绍最新2文件夹的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！