使用批处理脚本读取每5日线 [英] Read every 5th line using Batch Script

问题描述

我想和将显示一个文本文件的每一五号线，线一样没有1，6，11，16批处理程序....
我试图修改head.bat code在这里找到： Windows批处理命令（S）来读取文本文件第一行

I want to make a batch program with will display every 5th line of a text file, like line no 1, 6, 11, 16 .... I tried modifying head.bat code found here: Windows batch command(s) to read first line from text file

我的code是象下面这样：

My code is like below:

@echo off
setlocal enabledelayedexpansion
if [%1] == [] goto usage

SET /a counter=0

for /f "usebackq delims=" %%a in (%1) do (
set /a testcond=(%%counter-1)%4
if "!testcond!"=="0" echo %%a
set /a counter+=1
)

goto exit

:usage
echo Usage: fifth FILENAME

:exit

这code不工作。能否请你告诉我什么是错这个code？

This code is not working. Can you please tell me what is the wrong with this code?

推荐答案

好像你需要改变一行在脚​​本如下：

Seems like you need to change one line in your script as follows:

@echo off
setlocal enabledelayedexpansion
if [%1] == [] goto usage

SET /a counter=0

for /f "usebackq delims=" %%a in (%1) do (
set /a "testcond=(counter-1)%%5"
if "!testcond!"=="0" echo %%a
set /a counter+=1
)

goto exit

:usage
echo Usage: fifth FILENAME

:exit

现在脚本应该工作。

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