一个批处理文件，它的输出重定向已经重定向内从命令的输出？ [英] Redirect output from a command within a batch file whose output is already redirected?
问题描述
我已经搜查高有低，但是所有的建议和提示，我发现没有出于某种原因。我有一个被调用为这样一个批处理文件：
I've searched high and low, but all the suggestions and tips I've found do not work for some reason. I have a batch file that is being invoked as such:
cmd /C "automateMyProgram.bat >> automation.log 2>>&1"
这伟大工程：automation.log被加载的所有输出和错误为特定批处理文件。然而，批处理脚本中，我有以下命令：
That works great: automation.log gets loaded with all the stdout and stderr for that particular batch file. However, within that batch script I have the following command:
start php updateDB.php param1 param2 ^> updateDB.log
PHP脚本不会得到执行得很好，在参数就好读取，但updateDB.log永远不会创建。我保证PHP的错误在php.ini文件中报告设置为输出错误的命令行界面。有PHP脚本中的几个echo语句，我需要有记录到日志中，但它们不是出于某种原因输出。我读，如果你使用start命令调用的程序，您必须使用^操作符重定向输出，因为该程序是在一个新的进程开始了。我也试过：
The php script does get executed just fine and reads in the parameters just fine, but updateDB.log is never created. I ensured that php error reporting in the php.ini file is set to output errors to the command line interface. There are several echo statements within the php script that I need to have recorded to a log, but they are not being output for some reason. I read that if you use the start command to invoke a program, you must use the caret operator to redirect output since the program is started in a new process. I also tried:
start php updateDB.php param1 param2 >> updateDB.log
和那也不能工作。于是，我又试图：
and that didn't work either. So I then tried:
start /B "Database Update" "php" "param1" "param2" >> updateDB.log
而没有从批处理文件中工作，但它没有当我复制和直接粘贴入桌面上的一个cmd窗口。
and that didn't work from within the batch file, but it did when I copy and pasted it directly into a cmd window on the desktop.
任何可能你知道我可以重定向的PHP脚本的输出从批处理文件被调用？
Might any of you know how I can redirect the output of the php script being called from a batch file?
感谢您的时间和帮助！
推荐答案
这可能是最简单的解决方案：
This is probably the simplest solution:
start cmd /c "php updateDB.php param1 param2 > updateDB.log"
或者，如果你想在updateDB.log错误信息，
or, if you want to include error messages in updateDB.log,
start cmd /c "php updateDB.php param1 param2 > updateDB.log 2>&1"
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