如何创建Windows脚本唯一的输出文件名? [英] How to create a unique output filename for Windows Script?
问题描述
我想创建一个Windows脚本应该产生这样的文件名,每次我运行它:文件名1,文件名filename3等。以下是我迄今为止:
(
关闭@echo
WMIC逻辑磁盘的大小获得,自由空间,标题
)> disk.txt
我希望你能帮助我。谢谢!
::做出临时文件
:maketemp
SET临时文件=%TEMP%\\%随机%
如果不存在%临时文件%*(GOTO maketemp)ELSE(ECHO方式>%临时文件%A)
您现在有任何数量的可用文件名。
%临时文件%A
存在并且是空的,但%临时文件%anythingelse
应可供使用。
@ECHO OFF
SETLOCAL
SET基本名=文件名
SET / A outname = 0
:genloop
SET / A outname + = 1
如果不存在基本名称%%%outname%.TXTGOTO genloop
SEToutname =%基本名称%% outname%.TXTECHO%outname%GOTO:EOF
啊 - 递增每次运行的目标文件名。这应该做到这一点。它实际上不是创建一个文件 - 你需要创建文件%outname%
每次把它增加...
(之间的空间%基本名称%
和%outname%
是可选的,当然 - 如果需要,忽略它。)
编辑成包括 .TXT
I am trying to create a windows script that should generate this kind of filename everytime I run it: filename1, filename2, filename3 and so on. Here is what I have so far:
(
@echo off
wmic logicaldisk get size,freespace,caption
) > disk.txt
I hope you can help me. Thanks!!
:: make a tempfile
:maketemp
SET "tempfile=%temp%\%random%"
IF EXIST "%tempfile%*" (GOTO maketemp) ELSE (ECHO.>"%tempfile%a")
You now have any number of filenames available.
%tempfile%a
exists and is empty, but %tempfile%anythingelse
should be available for use.
@ECHO OFF
SETLOCAL
SET "basename=filename"
SET /a outname=0
:genloop
SET /a outname+=1
IF EXIST "%basename% %outname%.txt" GOTO genloop
SET "outname=%basename% %outname%.txt"
ECHO %outname%
GOTO :EOF
Ah - increment the destination filename on each run. This should do that. It's not actually creating a file - you'd need to create the file %outname%
each time to have it increment...
(the space between %basename%
and %outname%
is optional, of course - omit it if desired.)
edited to include .txt
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