创建一个批处理文件，对于简单的javac和java命令执行 [英] Creating a batch file, for simple javac and java command execution

问题描述

这是一个非常简单的事情，但我不能让我的头周围。我看过很多的StackOverflow职位和以及在互联网上。

我的目标是创建一个.BAT将打开cmd并执行我的Main.java到命令提示符。容易是吧，但我有困惑，怎么样？

下面我写这我的批处理文件应执行步骤

1. 开启CMD


2. 的javac Main.java


3. Java的主要

所以我假设我不需要给予明确的路径我的文件将驻留旁边，我所有的.java

我的理解迄今为止的研究：

1. 开启文本编辑器


2. 写一个code打开CMD（这我不知道如何）


3. 回声的javac Main.java（仍是模糊的概念对我来说）


4. 回声的Java主

另存为：name.bat

任何帮助将AP preciated。谢谢你。

解决方案

1. 打开记事本




2. 写

    关闭@echojavac的Main.javaJava的主要
    

3.saveAs blahblah.bat

确保Main.java居住与您的批处理文件和java路径ENV中设定。变量

4。在批处理文件双击，无需打开CMD明确TT将打开本身的.bat执行

It is a really simple thing but I cannot get my head around it. I have looked at plenty of StackOverFlow post and as well as on internet.

My goal is to create a .bat which will open cmd and execute my Main.java into command prompt. Easy isn't it, but I have got confused about how?

Below I am writing steps which my batch file should perform

1. open cmd
2. javac Main.java
3. java Main

My file will reside next to all my .java so I am assuming I don't need to give explicit path.

My understanding so far by research:

1. open text editor
2. write a code to open cmd(Which I am not sure how)
3. echo javac Main.java (Which is still fuzzy concept for me)
4. echo java Main

Save as: name.bat

Any help will be appreciated. Thank you.

解决方案

1. open notepad

2. write

   @echo off
   
   javac Main.java
   
   java Main
   

3.saveAs blahblah.bat

make sure that Main.java resides with your batch file and java path is set in env. variable

4 . double click on batch file, no need to open cmd explicitly tt will open itself on .bat execution

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