超过100个批处理文件越来越多 [英] Increasing numbers over 100 batch files

问题描述

我试图写一个Windows 7的一个批处理文件，将创建100名的文本文件 - EX1至EX100。在每一个文件，我需要使用相同的文字作为文件名来替换给定文本（如EX3）。

I am trying to write a batch file for Windows 7 that will create 100 text files with names - ex1 to ex100. In each file i need to replace a given text (eg. ex3) with the same text as the name of the file.

到目前为止，我已经设法让该批处理文件来创建100个文件但是文本（EX3）是通过EX1在每个文件所取代。

So far I have managed to get the batch file to create the 100 files however the text (ex3) is replaced by ex1 in each file.

下面是我用code。我是一个完整的新手到这一点，从我发现位拼凑起来的。

Here is the code that I have used. I am a complete novice to this and have cobbled it together from bits that I have found.

@echo off
setlocal enabledelayedexpansion

FOR /F "usebackq delims=" %%G IN ("c:\batch\batch.txt") DO (
  Set Line=%%G
  Set Line=!Line:"='!
  Call:replace "!Line!"
)

pause


goto:eof ------------
  :replace subroutine
  (Set Line=%*&Set Line=!Line:~1,-1!)
  Set Line=!Line:'="!

For /l %%A in (7,1,100) do Set "Line=!Line:ex3=ex%%A!"  
For /l %%n in (1,1,100) do echo.!Line! >>"c:\batch\ex%%n.txt"

 goto:eof ------------

有什么建议？

推荐答案

哇 - 这code是方式更令人费解的比需要的（也是缓慢的，因为CALL的）

Wow - that code is way more convoluted than is needed (and also slow because of CALL).

@echo off
setlocal enableDelayedExpansion
set "folder=c:\batch"
for /l %%N in (1 1 100) do del "%folder%\ex%%N.txt" 2>nul
for /f "usebackq delims=" %%A in ("%folder%\batch.txt") do (
  set "line=%%A"
  for /l %%N in (1 1 100) do (echo !line:ex3=ex%%N!)>>"%folder%\ex%%N"
)

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