如何在BATCH字符串中提取数 [英] How to extract number from string in BATCH

问题描述

我想先抽取号码，在路径字符串中。

一些例子

  C：\\目录\\ release1 \\ TEMP应提取：1
C：\\目录\\ release11 \\ TEMP应提取：11
C：\\目录\\ release1 \\ TEMP \\ REL2应提取：1
C：\\目录\\ release15a \\ TEMP应提取：15
 

我目前的code，即循环槽文件夹名称，并测试文件夹的名字是一个数字（我在这里需要一些变化）：

  SETLOCAL ENABLEEXTENSIONS enabledelayedexpansion
集线等于一\\ 2 \\ 3 \\ 4 \\宠物\\ 0 \\ SEST \\ REL6 \\一
REM SET行=％CD％
：processToken
FOR / F令牌= 1 * delims = \\%%一中（％线％）做（
回声令牌：%%一
集线= %% b
REM修复需要的位置：需要从字符串中提取数
呼应%%一个| FINDSTR / R / C：^ [0-9] [0-9] * $＆GT; NUL
如果错误级别1（回声非数字）其他（回声号）
）
如果不是％线％==GOTO：processToken
ENDLOCAL
 

谢谢！

编辑：
我想从路径字符串解析数。
好吧，我已经找到了解决方案，只检查字符串的最后3个字符。这是确定现在。

  ::测试最后3个字符
设置RELNO =令牌：〜-3,3！
回声令牌：〜-3,3 | FINDSTR / R / C：！^ [0-9] * $＆GT; NUL
如果错误级别1（不呼应号）其他（回声号）::测试最后2个字符
设置RELNO =令牌：〜-2,2！
回声令牌：〜-2,2 | FINDSTR / R / C：！^ [0-9] * $＆GT; NUL
如果错误级别1（不呼应号）其他（回声号）::测试最后一个字符
设置RELNO =令牌：〜！1,1！
回声令牌：〜-1,1 | FINDSTR / R / C：！^ [0-9] * $＆GT; NUL
如果错误级别1（不呼应号）其他（回声号）
 

解决方案

好吧，这里有一批唯一版本。它实现ISDIGIT，走输入寻找第一位数字，并停止并打印时它击中端或一个非数字的字符。

这是缓慢的 - 越长的输入，速度较慢是

。

  @setlocal
关闭@echo
REM extractfirstnumber.bat
REM鉴于可能包含数字的字符串，打印的第一个整数。
REM 123test456  - ＆GT; 123
REM注意，特殊字符可能无法妥善处理。 （例如，）
REM http://stackoverflow.com/questions/6120623/how-to-extract-number-from-string-in-batch
组输入=％1
如果（％输入％）==（）转到：EOF
拨打：firstnum输入输出
如果不是（％输出％）==（）呼应％输出％和放大器;＆安培;转到END_SUCCESS
转到end_fail：END_SUCCESS
ENDLOCAL
@exit / B 0：end_fail
ENDLOCAL
@exit / B 1：firstnum
SETLOCAL ENABLEDELAYEDEXPANSION
呼叫建立串= %%%〜1 %%
集/ A指数= 0
设置return_number =
转到firstnum_loop：firstnum_loop
如果（字符串：！〜％索引％，1）==（）转到firstnum_end
设置test_char =字符串：！〜％索引％，1！
拨打：ISDIGIT test_char is_digit
REM发现一个数字？将它添加到回报。
如果（％is_digit％）==（真）设置return_number =％return_number %% test_char％
REM发现了一个没有数字？如果我们发现之前，结束一个数字。
如果（％is_digit％）==（假）如果不是（％return_number％）==（）转到firstnum_end
集/ A指数=％索引％+ 1
转到firstnum_loop：firstnum_end
（ENDLOCAL＆安培; REM返回值
    IF％〜2NEQSET％〜2 =％return_number％
）
GOTO：EOF：ISDIGIT
SETLOCAL ENABLEDELAYEDEXPANSION
组号码= 1234567890
设置found_number = FALSE
呼叫建立串= %%%〜1 %%
REM如果传递的字符串没有一个单个字符，以虚假立即返回。
如果（％字符串：〜0.1％）==（）转到isdigit_end
如果不是（％字符串：〜1,1％）==（）转到isdigit_end
集/ A指数= 0
转到isdigit_loop：isdigit_loop
如果（号码：！〜％索引％，1）==（）转到isdigit_end
设置test_char =号码：！〜％索引％，1！
如果（％test_char％）==（％字符串％），设置found_number =真放;＆安培;转到isdigit_end
集/ A指数=％索引％+ 1
转到isdigit_loop：isdigit_end
（ENDLOCAL＆安培; REM返回值
    IF％〜2NEQSET％〜2 =％found_number％
）
GOTO：EOF
 

示例输出：

  C：\\＆GT; extractfirstnumber C：\\目录\\ release1 \\ TEMP
1
C：\\＆GT; extractfirstnumber C：\\目录\\ release11 \\ TEMP
11
C：\\＆GT; extractfirstnumber C：\\目录\\ release1 \\ TEMP \\ REL2
1
C：\\＆GT; extractfirstnumber C：\\目录\\ release15a \\ TEMP
15
 

I would like to extract first number, found in a path string.

Some examples

c:\dir\release1\temp  should extract: 1
c:\dir\release11\temp  should extract: 11
c:\dir\release1\temp\rel2  should extract: 1
c:\dir\release15a\temp  should extract: 15

My current code, that loops trough folder names, and tests if folder name is a number (I need some changes here):

setlocal enableextensions enabledelayedexpansion
set line=one\two\three\4\pet\0\sest\rel6\a
rem set line=%cd%
:processToken
for /f "tokens=1* delims=\" %%a in ("%line%") do (
echo Token: %%a
set line=%%b
rem need fix here: need to extract number from string
echo %%a|findstr /r /c:"^[0-9][0-9]*$" >nul
if errorlevel 1 (echo not a number) else (echo number)
)
if not "%line%" == "" goto :processToken
endlocal

Thanks!

EDIT: I wanted to parse number from that path string. Well I've found solution that checks only last 3 characters of string. It's ok for now.

::test last 3 characters
set relno=!token:~-3,3!
echo !token:~-3,3!|findstr /r /c:"^[0-9]*$" >nul
if errorlevel 1 (echo not number) else (echo number)

::test last 2 characters
set relno=!token:~-2,2!
echo !token:~-2,2!|findstr /r /c:"^[0-9]*$" >nul
if errorlevel 1 (echo not number) else (echo number)

::test last character
set relno=!token:~-1,1!
echo !token:~-1,1!|findstr /r /c:"^[0-9]*$" >nul
if errorlevel 1 (echo not number) else (echo number)

解决方案

Okay, here's a batch only version. It implements isdigit, walks the input looking for the first digit, and stops and prints the characters between when it hits the end or a non-digit.

This is slow - the longer the input, the slower it is.

@setlocal
@echo off
rem extractfirstnumber.bat
rem Given a string possibly containing a number, print the first integer.
rem 123test456 -> 123
rem Note that special characters may not be properly handled.  (e.g. , ;)
rem http://stackoverflow.com/questions/6120623/how-to-extract-number-from-string-in-batch
set input=%1
if ("%input%") == ("") goto :eof
call :firstnum input output
if not ("%output%") == ("") echo %output%&&goto end_success
goto end_fail

:end_success
endlocal
@exit /b 0

:end_fail
endlocal
@exit /b 1

:firstnum
SETLOCAL ENABLEDELAYEDEXPANSION
call set "string=%%%~1%%"
set /a index = 0
set return_number=
goto firstnum_loop

:firstnum_loop
if ("!string:~%index%,1!") == ("") goto firstnum_end
set test_char=!string:~%index%,1!
call :isdigit test_char is_digit
rem Found a digit?  Add it to the return.
if ("%is_digit%") == ("true") set return_number=%return_number%%test_char%
rem Found a not-digit?  If we found a digit before, end.
if ("%is_digit%") == ("false") if not ("%return_number%") == ("") goto firstnum_end
set /a index = %index% + 1
goto firstnum_loop

:firstnum_end
( ENDLOCAL & REM RETURN VALUES
    IF "%~2" NEQ "" SET "%~2=%return_number%"
)
goto :eof

:isdigit
SETLOCAL ENABLEDELAYEDEXPANSION
set NUMBERS=1234567890
set found_number=false
call set "string=%%%~1%%"
REM If the passed string does not have a single character, return immediately with false.
if ("%string:~0,1%") == ("") goto isdigit_end
if not ("%string:~1,1%") == ("") goto isdigit_end
set /a index=0
goto isdigit_loop

:isdigit_loop
if ("!NUMBERS:~%index%,1!") == ("") goto isdigit_end
set test_char=!NUMBERS:~%index%,1!
if ("%test_char%") == ("%string%") set found_number=true&&goto isdigit_end
set /a index = %index% + 1
goto isdigit_loop

:isdigit_end
( ENDLOCAL & REM RETURN VALUES
    IF "%~2" NEQ "" SET "%~2=%found_number%"
)
goto :eof

Sample output:

C:\>extractfirstnumber c:\dir\release1\temp
1
C:\>extractfirstnumber c:\dir\release11\temp
11
C:\>extractfirstnumber c:\dir\release1\temp\rel2
1
C:\>extractfirstnumber c:\dir\release15a\temp
15

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