打开网站的网址通过使用批处理文件和参数链接 [英] Open website url links with parameter by using a batch file
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问题描述
我试图打开在我的浏览器参数一些网站的URL链接。我用这个code做了一个批处理文件:
关闭@echo
启动图像www.images.com/1000/image.jpg
启动图像www.images.com/1001/image.jpg
启动图像www.images.com/1002/image.jpg
...
...
启动图像www.images.com/5000/image.jpg
我要的是创造一个for循环,将做到这一点:
有关(I = 1000; I< 5000;我++)
{
启动图像www.images.com/i/image.jpg
}
,其中i是网站的链接的一个参数。我在批处理文件中创建新的,我无法弄清楚如何使它发挥作用。我想这一个,但它没有工作:
为我在{} 1000..5000
做
启动图像www.images.com/$i/image.jpg
这个问题的第一步。然后,我要救这个链接显示的图像,只有当链接是有效的(不是死像403,404错误)
解决方案
有关/ L %% i的(1000,1,5000)做(
启动图像www.images.com/%%i/image.jpg
)
I am trying to open some website url links with a parameter in my browser. I made a batch file using this code :
@echo off
start "images" "www.images.com/1000/image.jpg"
start "images" "www.images.com/1001/image.jpg"
start "images" "www.images.com/1002/image.jpg"
...
...
start "images" "www.images.com/5000/image.jpg"
All I want is to create a For loop that will do that :
For (i=1000; i<5000 ; i++)
{
start "images" "www.images.com/i/image.jpg"
}
where "i" is a parameter of the website link. I am new in the batch file creation and I cannot figure out how to make it work. I tried this one but it did not work:
for i in {1000..5000}
do
start "images" "www.images.com/$i/image.jpg"
This question is a first step. Then i want to save the images shown on this links, only if the links are valid (not dead like in 403, 404 errors)
解决方案
For /L %%i in (1000,1,5000) do (
start "images" "www.images.com/%%i/image.jpg"
)
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