批处理文件比较两个文件夹退回没有一个文件夹中的文件 [英] Batch file compare two folders return files that aren't in one folder

问题描述

我试图做一个批处理文件，将比较两个文件夹的核心和自定义，退回没有自定义的文件的名称。

到目前为止，我有这个code，其中大部分是采取形式堆栈溢出另一个问题。它创建的每个文件夹中的文件阵列。我如何比较呢？

 关闭@echo
SETLOCAL enableDelayedExpansion文件夹::打造阵
设置fold​​erCnt = 0
FOR / FEOL =：delims =%% f由于（'DIR / B核）做（
  集/ A folderCnt + = 1
  设置文件夹！folderCnt！= %% F
）::打印菜单
在/ L %% M（11％folderCnt％）做回声%%米 - ！文件夹%%中号！
回声（文件夹::打造阵
设置fold​​erCnt = 0
FOR / FEOL =：delims =%% f由于（'DIR / B定制​​'）做（
  集/ A folderCnt + = 1
  设置文件夹！folderCnt！= %% F
）::打印菜单
对/ L %% N的（11％folderCnt％）做回声%% N  - ！文件夹%% N！
回声（暂停test.bat的
 

解决方案

如何

 回声Y | XCOPY / L / D核心\\ *定制\\
 

这应该列出所有的核心不在定制或不同版本的核心？文件

I'm trying to make a batch file that will compare two folders "core" and "custom" and return the names of the files that aren't in custom.

So far I have this code, most of which is taken form another question on stack overflow. It creates "Arrays" of the files in each folder. How can I compare them?

@echo off
setlocal enableDelayedExpansion

::build "array" of folders
set folderCnt=0
for /f "eol=: delims=" %%F in ('dir /B core') do (
  set /a folderCnt+=1
  set "folder!folderCnt!=%%F"
)

::print menu
for /l %%M in (1 1 %folderCnt%) do echo %%M - !folder%%M!
echo(

::build "array" of folders
set folderCnt=0
for /f "eol=: delims=" %%F in ('dir /B custom') do (
  set /a folderCnt+=1
  set "folder!folderCnt!=%%F"
)

::print menu
for /l %%N in (1 1 %folderCnt%) do echo %%N - !folder%%N!
echo(

pause

test.bat

解决方案

how about

echo y|xcopy /l /d core\* custom\

which should list all the files in core that are not in custom or a different version is in core?

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