嵌套for循环批处理 [英] Nested For Loop in Batch

问题描述

伊夫过目许多线程，似乎无法的解决方案放在一起我的问题。

Ive look over many threads and cannot seem to put together a solution to my problem.

我想什么做的是使用两个列表创建一个输出。

What i would like to do is use two lists to create one output.

set Client_ID=BJCH,BORG,FGMS,SVIN,JEFF,NWIL
set PartNo=1,2,9,10,12,20

for %%A in (%Client_ID%) do (
    for %%B in (%PartNo%) do (
        echo %%A %%B 

        )
)

但输出我得到的是：

But the output I get is:

BJCH 1
BJCH 2
BJCH 9
BJCH 10
BJCH 12
BJCH 20
BORG 1
BORG 2
BORG 9
BORG 10
BORG 12
BORG 20
FGMS 1
FGMS 2
FGMS 9
etc........

我需要的是

BJCH 1
BORG 2
FGMS 9
SVIN 10
JEFF 12
NWIL 20

任何想法，我做错了什么？任何帮助深表AP preciated。

Any idea what I'm doing wrong? Any help is much appreciated.

推荐答案

您两份名单是的分离的人的：如果你窝有一个为进入另外一个，你的乘法的结果的数量。有没有办法处理的两个列表的在同一个为，除非你转换成列出两个<一个href=\"http://stackoverflow.com/questions/10166386/arrays-linked-lists-and-other-data-structures-in-cmd-exe-batch-script/10167990#10167990\">arrays然后处理在同一个两个数组为，也就是过程中的两个数组有相同索引的元素。例如：

Your two lists are separated ones: if you nest one for into the other one, you are multiplying the number of results. There is no way to process both lists in the same for, unless you convert the lists into two arrays and then process both arrays in the same for, that is, process the elements of the two arrays with same index. For example:

setlocal EnableDelayedExpansion

set Client_ID[1]=BJCH
set Client_ID[2]=BORG
etc...

set PartNo[1]=1
set PartNo[2]=2
etc...

for /L %%i in (1,1,6) do echo !Client_ID[%%i]! !PartNo[%%i]!

您还可以模拟previous处理（与指数相同的两个元素）是这样的：

You may also simulate previous processing ("two elements with same index") this way:

@echo off
setlocal EnableDelayedExpansion

set Client_ID=BJCH,BORG,FGMS,SVIN,JEFF,NWIL
set PartNo=1,2,9,10,12,20

set i=0
for %%A in (%Client_ID%) do (
   set /A i+=1, j=0
   for %%B in (%PartNo%) do (
      set /A j+=1
      if !i! equ !j! echo %%A %%B 
   )
)

修改：补充输出实例的

BJCH 1
BORG 2
FGMS 9
SVIN 10
JEFF 12
NWIL 20

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