美丽的汤获得的第一个孩子 [英] Beautiful soup getting the first child

问题描述

我怎样才能获得的第一个孩子？

How can I get the first child?

 <div class="cities"> 
       <div id="3232"> London </div>
       <div id="131"> York </div>
  </div>

我怎样才能得到伦敦？

How can I get London?

for div in nsoup.find_all(class_='cities'):
    print (div.children.contents)

AttributeError的：'的ListIterator'对象有没有属性'的内容

AttributeError: 'listiterator' object has no attribute 'contents'

推荐答案

div.children返回迭代器。

div.children returns an iterator.

for div in nsoup.find_all(class_='cities'):
    for childdiv in div.find_all('div'):
        print (childdiv.string) #london, york

AttributeError的升高，因为像的'\\ n'无标签，在。孩子。只要使用适当的儿童选择器来查找特定的div。

AttributeError was raised, because of non-tags like '\n' are in .children. just use proper child selector to find the specific div.

（更多编辑）无法重现你的异常 - 这里就是我所做的：

(more edit) can't reproduce your exceptions - here's what I've done:

In [137]: print foo.prettify()
<div class="cities">
 <div id="3232">
  London
 </div>
 <div id="131">
  York
 </div>
</div>

In [138]: for div in foo.find_all(class_ = 'cities'):
   .....:     for childdiv in div.find_all('div'):
   .....:         print childdiv.string
   .....: 
 London 
 York 

In [139]: for div in foo.find_all(class_ = 'cities'):
   .....:     for childdiv in div.find_all('div'):
   .....:         print childdiv.string, childdiv['id']
   .....: 
 London  3232
 York  131

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